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pochemuha
2 years ago
10

Determine the unknown mineral using the information given below. Be sure to use significant figure rules when doing calculations

. Mass is shown on the triple beam. Scale Test Mineral Mineral H. Density, g/cc 10 diamond tellurium 2 2.07 9 corundum galena 2.5 7.58 8 topaz anglesite 2.5 - 3 6.4 7 quartz chalcocite 2.5 - 3 5.6 6 feldspar copper 2.5 - 3 9.0 5 apatite gold 2.5 - 3 19.3 4 fluorite silver 2.5 - 3 10.5 3 calcite arsenic 3.5 5.7 2 gypsum barite 3 - 3.5 4.4 1 talc dolomite 3.5 - 4 2.9 platinum 4.5 21.5 willemite 5.5 4.0 magnetite 6 5.18 pyrite 6 - 6.5 5.02 pyrolusite 6 - 6.5 5.0 cassiterite 6.5 6.9 diamond 10 3.52 Volume of water displaced = 0.051 L
Mass: 981.0, 908, 908.1, 981 g
Density: 192.35, 19,235, 19, 19.2 g/cc
Hardness 4, 2.5, 1, 3, 5.5 - 5, 3, 2, 4.5, 1.5
Determine the unknown mineral.
Platinum, Gold
Chemistry
1 answer:
Ivenika [448]2 years ago
6 0

The unknown mineral is gold because of the similar properties of gold to that unknown mineral.

<h3>What is unknown mineral?</h3>

The unknown mineral is Gold because it has similar properties to the gold. Gold has density of 19.3 grams per cubic centimeter which is same to this unknown mineral. The hardness and mass of the mineral are also similar to the Gold.

So we can conclude that the unknown mineral is gold because of the similar properties of gold to that unknown mineral.

Learn more about mineral here: brainly.com/question/15844293

#SPJ1

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8 0
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When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas
luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

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By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = \frac{1}{764}\times 581=0.7605mol

To calculate mass for given number of moles, we use the equation:

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Putting values in above equation, we get:

0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g

Hence, the mass of methanol that must be burned is 24.34 grams

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