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3 years ago

Carbonic acid (H2CO3) forms when carbon dioxide (CO2) dissolves in water according to this equation:

2 answers:

5 0

In order to determine how many moles of CO2 provide 2 moles of H2CO3, we must look at the balanced reaction and compare the coefficients of each compound.

CO2 + H2O --> H2CO3

The equation above is already balanced; therefore, for every 1 mole of CO2, we get 1 mole of H2CO3.

2 moles H2CO3 x (1 mole CO2)/(1 mole H2CO3) = 2 moles CO2.

We simply convert the moles of H2CO3 to moles of CO2, which results in 2 moles of CO2 required to give 2 moles of H2CO3.

Llana [10]3 years ago

3 0

Answer:

2 mol

Explanation:

The other answer explained it perfectly! I just wanted to confirm this as correct! :)

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Which type of reaction occurs when 50mL quantities of 1 M Ba(OH)2 (aq) and H2SO4 (aq) are combined

iragen [17]

Double replacement.

Ba(OH)2 + H2SO4 ====> 2H2O + BaSO4

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3 years ago

What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?

frosja888 [35]

The volume of 0. 250 mole sample of $H_{2}$ gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is 3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

P is the pressure of the hydrogen gas = 1.7 atm
Vis the volume of the hydrogen gas = ?
n is the number of the hydrogen gas = 0.25 mole
R is the universal gas constant = 0.082 atm L/mole K
T is the temperature of the sample = 35°C = 35 + 273 = 308 K

By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is 3.71 L.

learn more about ideal gas equation

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4 0

1 year ago

What is the freezing point depression of a solution that contains 0.705?

Sveta_85 [38]

Colligative properties calculations are used for this type of problem. Calculations are as follows:

ΔT(freezing point) = (Kf)m
ΔT(freezing point) = 1.86 °C kg / mol (0.705)
ΔT(freezing point) = 1.3113 °C

Hope this answers the question. Have a nice day.

6 0

3 years ago

Hi, can someone help me balance this chemistry equation: H2SO4 + RbOH -> Rb2SO4 + H2O

zloy xaker [14]

H2SO4 + 2RbOH -> Rb2SO4 + 2H2O

If you want an explanation, keep reading.

In the first portion, there are two hydrogen ions and four sulfate ions.

The second portion has one rubidium ions and one hydroxide ion.

On the other side of the equation, in order to keep those two rubidiums balanced, you'll need to add a two at the beginning of the second portion, but in that process you are giving a second hydroxide value.

Back to the right side, there is there is water (H2O).

On the first portion, there were two hydrogen ions. The second portion also has two hydroxides because of the value change (adding the two to the front).

So on the fourth portion, you'd have to add another two so you could balance the four hydrogen ions (H2 and 2OH) and the two oxygen ions (2OH).

I hope this was easy to understand.

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3 years ago

There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc

zhuklara [117]

Answer:

$K_{sp}$ of $Zn(CH_{3}COO)_{2}$ is 0.0513