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Dahasolnce [82]
3 years ago
6

Carbonic acid (H2CO3) forms when carbon dioxide (CO2) dissolves in water according to this equation:

Chemistry
2 answers:
forsale [732]3 years ago
5 0
In order to determine how many moles of CO2 provide 2 moles of H2CO3, we must look at the balanced reaction and compare the coefficients of each compound.

CO2 + H2O --> H2CO3

The equation above is already balanced; therefore, for every 1 mole of CO2, we get 1 mole of H2CO3.

2 moles H2CO3  x (1 mole CO2)/(1 mole H2CO3) = 2 moles CO2.

We simply convert the moles of H2CO3 to moles of CO2, which results in 2 moles of CO2 required to give 2 moles of H2CO3.
Llana [10]3 years ago
3 0

Answer:

2 mol

Explanation:

The other answer explained it perfectly! I just wanted to confirm this as correct! :)

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Given pH = 8.55 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
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Answer:

Explanation:

The given pH = 8.55

Unknown:

[H₃O⁺] = ?

[OH⁻] = ?

In order to find these unknowns we must first establish some relationship.

                      pH = -log[H₃O⁺]

                   8.55 = -log[H₃O⁺]

                    [H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³

To find the [OH⁻],

                     pH + pOH = 14

                               pOH = 14 - pH = 14 - 8.55

                                pOH = 5.45

              pOH = -log[OH⁻]

               [OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³

The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.

7 0
4 years ago
A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from
ratelena [41]

Answer:  Approximately 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

===================================================

Work Shown:

We have the following variables

  • Q = 714 joules = heat required
  • m = 52 grams = mass
  • c = specific heat = unknown
  • \Delta t = 82-30.5 = 51.5 = change in temperature

note: the symbol \Delta is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\

The specific heat of the unknown metal is roughly 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

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3 years ago
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