Answer:
The balanced chemical equation will be "
".
Explanation:
The given equation is:

<u>Step 1:</u>
<u></u>
...(equation 1)
<u>Step 2:</u>
<u></u>
...(equation 2)
On adding "equation 1" and "equation 2", we get
⇒ 
⇒ 
The second step:
⇒ 
Answer:
Appearing disoriented, such as swimming upside down.
Leaving food uneaten.
White spots on fins or body.
Discolored gills.
Explanation:
Gold Fish are unable to regulate their body temperature, so they are influenced by the temperature around them. If the water is warm, gold fish metabolism accelerates, feeding and respiration increases, and there is a general increase in movement. If the water is cooler, fish become lethargic and tend to be inactive.
Answer: The concentration of the acid is 0.01 moles acid/0.040 L = 0.25 moles/L = 0.25 M
Explanation:
<u>Answer:</u> The freezing point of solution is -0.454°C
<u>Explanation:</u>
Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.
The equation used to calculate depression in freezing point follows:

To calculate the depression in freezing point, we use the equation:

Or,

where,
Freezing point of pure solution = 0°C
i = Vant hoff factor = 2
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (KCl) = 5.0 g
= Molar mass of solute (KCl) = 74.55 g/mol
= Mass of solvent (water) = 550.0 g
Putting values in above equation, we get:

Hence, the freezing point of solution is -0.454°C
The value of ΔG° at this temperature is -18034.18 J/mol
Calculation,
Given information
formation constant (Kf)= 1.7 × 
Universal gas constant (R) = 8.314 J/K• mol
Temperature = 25° C = 25 °C + 273 = 300 K
Formula used:
ΔG° = -RT㏑Kf
By putting the valur of R,T, Kf we get the value of ΔG°
ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × 
ΔG° = -2494.2㏑ 1.7 ×
= -18034.18 J/mol
So, change in standard Gibbs's free energy is -18034.18 J/mol
Learn about formation constant
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