Answer:
(40 + 2x)feet
Step-by-step explanation:
see attachment for the figure.
Let 'L' represents the length of the rectangular swimming pool i.e 40ft wide.
and pool is bordered by square tiles that are x feet in length surrounding the pool
therefore,
In order to find the longest side of the pool and the tile border, take the sum of length of the swimming pool i.e 40 adding two times the wide of the square tiles
(40+2x)feet.
Please, next time, please share the graph referred to in the problem statement.
You are comparing f(x)=2 ln x and g(x) = 4 ln x. The two graphs look the same, except that the amplitude (rise) in 4 ln x is exactly twice that in 2 ln x.
Thus, if 2 ln x = 3, 4 ln x = 2(3) = 6.
Answer:
24 trees per acre
Step-by-step explanation:
Let x be the optimal tree density per acre and y be the number of bushels yield per tree
Since for each unit change of x from 28 trees/acre, we have 2 unit change of y from 40 bushels per tree in the reversed direction
Change of x from 28 is x - 28
Change of y from 40 is y - 40
Therefore we have y - 40 = -2(x - 28) or y = 40 - 2(x - 28) = -2x + 96
The total bushels per acre should be y bushels/tree * x tree/acre. We want to optimize this. Substitute the above equation in for y and we have


To find the maximum value of this, we can take the first derivative and set it to 0



We know this is a maxima because
. So T is maximum when x = 24 trees per acre
Answer:
-11, -5, -23, 7
Step-by-step explanation:
plug in the h value into equation
-2(2)-7
-11
-2(-1)-7
-5
-2(8)-7
-23
-2(-7)-7
7
676 is the answer to 500+150+20+6