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adelina 88 [10]
3 years ago
12

Consider testing Upper H 0 : mu equals 20H0: μ=20 against Upper H Subscript a Baseline : mu less than 20Ha: μ<20 where muμ is

the mean number of latex gloves used per week by all hospital​employees, based on the summary statistics nequals=444, x overbarxequals=19.3 and sequals=11.1 Complete parts a and b.

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

Test: \mu < 20 with normal distⁿ

Hypothesis test:

H0:  \mu \ge 20                         (Null Hypothesis, H₀ : \mu = 20 is also correct)

H1: \mu < 20                             (Alternative Hypothesis, also called H₁)

This is lower tailed test.

Since sample is large, sample standard deviation can be taken as an  approximation of population standard deviation.

x = 19.3

\sigma = 11.1

n = 444

significance level, \alpha = 0.05 (If no value is given, we take level of 0.05)

Test statistic z* = \frac{x-\mu}{\sigma/\sqrt{n}}

         

                         = \frac{19.3-20}{11.1/\sqrt{444}}

                       = - 1.33

The attached files contains additional information

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To solve for 'x' we need to isolate it, by getting all terms with 'x' on one side of the equation and all terms without 'x' on the other side.

To do this we can start by subtracting 51 from both sides of the equation:
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