Answer:
Step-by-step explanation:
Given
When mass = 4kg; Acceleration = 15m/s²
Required
Determine the acceleration when mass = 10kg, provided force is constant;
Represent mass with m and acceleration with a
The question says there's an inverse variation between acceleration and mass; This is represented as thus;
Convert variation to equality
; Where F is the constant of variation (Force)
Make F the subject of formula;
When mass = 4kg; Acceleration = 15m/s²
When mass = 10kg; Substitute 60 for Force
Divide both sides by 10
<em>Hence, the acceleration is </em><em />
(B) 8 less than the product of 3 and n
Here, we are given an equation 3n - 8
Let us consider each of the options one by one
(A) the product of 3, n and 8 will be written as 24n. Hence this isn't the correct answer.
(B) 8 less than the product of 3 and n will be written as 3n - 8. This matches our equation and hence is the correct answer.
(C) n minus 8 times 3 will be written as 24 - n. Hence, this is also incorrect.
(D) 3 times n less than 8 will be written as 8 - 3n. Thus, this is also eliminated.
Therefore, option B is the correct answer.
Learn more about expressing equations here-
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Answer: a^3+81ab^2
First, you square (a+9b) which will become (a^2+81b^2)
Then, you multiply it by a and you will get a^3+81ab^2
I hope this helps you
log6 [x. (2x-7)]=log6 (6^2)
x. (2x-7)=36
2x^2-14x-36=0
2x +4
x -9
(2x+4)(x-9)=0
x= -2
x=9
