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ira [324]
3 years ago
5

Write the Henderson-Hasselbalch equation for a solution of formic acid. Calculate the quotient [HCO2]/[HCO2H] at (a) pH 3.000; (

b) pH 3.744; (c) pH 4.000.
Chemistry
1 answer:
Elena L [17]3 years ago
3 0

Answer:

a. 0.182

b. 1.009

c. 1.819

Explanation:

Henderson-Hasselbach equation is:

pH = pKa + log [salt / acid]

Let's replace the formula by the given values.

a. 3 = 3.74 + log [salt / acid]

3 - 3.74 = log [salt / acid]

-0.74 = log [salt / acid]

10⁻⁰'⁷⁴ = 0.182

b. 3.744 = 3.74 + log [salt / acid]

3.744 - 3.74 = log [salt / acid]

0.004 = log [salt / acid]

10⁰'⁰⁰⁴ = 1.009

c. 4 = 3.74 + log [salt / acid]

4 - 3.74 = log [salt / acid]

0.26 = log [salt / acid]

10⁰'²⁶ = 1.819

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The correct answer is D. How gravity interacts with planets

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Einstein's theory of relativity formulated in 1915 introduces the following concepts:

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8 0
3 years ago
What happens if the same zero error occurs in every reading
nadya68 [22]

Zero error occur in every reading means that the measuring instrument needs to recalibrated and adjusted.

<h3>What is Zero error?</h3>

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3 0
1 year ago
Find the percent composition of water in barium chloride dihydrate. Round your answer to the
nadya68 [22]

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Explanation:

7 0
2 years ago
According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams
e-lub [12.9K]

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.

Unsaturated solution has solute in lower proportions than required to form a saturated solution.

Supersaturated solution has solute in amounts greater than a saturated solution.

We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.

The solubility of KI at 10^{0}C is 136 g/ 100 mL water

The solubility of KNO_{3} at 10^{0}C is 21 g/100 mL water.

The solubility of NaNO_{3} at 10^{0}C is 80 g/100 mL water.

The solubility of NaCl at 10^{0}C is 38 g/ 100 mL water.

So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at 10^{0}C.So, if we have 80g KI/ 100mL water it would be an unsaturated solution.

4 0
3 years ago
Read 2 more answers
Sodium hydroxide, NaOHNaOH; sodium phosphate, Na3PO4Na3PO4; and sodium nitrate, NaNO3NaNO3, are all common chemicals used in cle
nadya68 [22]

Answer:

NaOH > Na3PO4 > NaNO3

Explanation:

in NaOH

23/40 * 100 = 57.5%

in Na3PO4

3 * 23/164 * 100 = 42%

In NaNO3

23/85 * 100 = 27.1%

Hence;

NaOH > Na3PO4 > NaNO3

4 0
3 years ago
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