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Oxana [17]
3 years ago
9

Given the information shown in process "B", calculate the molar enthalphy of fusion for ice

Chemistry
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

D) 6.02 kJ/mol

Explanation:

Hello,

In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:

n=\frac{1.5kg}{18kg/kmol} *\frac{1000mol}{1kmol}=83.33mol

Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:

\Delta H_{fusion}=\frac{500kJ}{83.33mol}\\ \\\Delta H_{fusion}=6.02kJ/mol

Hence answer is D) 6.02 kJ/mol.

Best regards.

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From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

The balanced chemical reaction for the synthesis of silver chloride has been:

\rm AgNO_3\;+\;NaCl\;\rightarrow\;AgCl\;+\;NaNO_3

From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.

The moles of silver nitrate available are,  \rm M_A_g_N_O_3=15\;mol

The moles of silver nitrate produced can be given as:

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Thus, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

For more information about moles produced, refer to the link:

brainly.com/question/10606802

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