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monitta
3 years ago
6

During the winter months, many locations experience snow and ice storms. It is a common practice to treat roadways and sidewalks

with salt, such as CaCO3 . If a 11.3 kg bag of CaCO3 is used to treat the sidewalk, how many moles of CaCO3 does this bag contain?
Chemistry
1 answer:
Luden [163]3 years ago
5 0

Answer:

The number of moles of CaCO3 on the bag is 112.90 moles

Explanation:

number mole (n) = mass (m) divided by molecular mass (Mm)

Mm of CaCO3 = 100.0869 g/mole

mass in grams = 11.3 Kg x (10^3 g/1 Kg) = 11300 grams

number of moles (n) = 11300 grams divided by 100.0869 grams per mole = 112.90 moles of CaCO3 in the bag.

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How many atoms are in 0.075 mol of titanium?
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The mass of titanium is = 47,867 g/1mol

Applying the rule of avrogado

1mol _______ 6,023 × 10^(23) at

0,075mol ___ x


X . 1mol = 0,075mol . 6,023 . 10^(23)at

X = 0,075 . 6,023 . 10^(23) at

X = 4,51 . 10^(22) atoms

Hope this helps
7 0
3 years ago
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Chlorine has two naturally stable isotopes: 35Cl (34.968853 amu) and 37Cl (36.965903 amu). The natural abundance of each isotope
allochka39001 [22]

Answer:

35Cl ⇒ 34.968853 amu  has an abundance of 30.05%

Explanation:

The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.

There are 2 naturally stable isotopes, this means together they have an abundance of 100%

The isotopes are:

35Cl ⇒ 34.968853 amu  has an abundance of X %

37Cl ⇒ 36.965903 amu  has an abundance of Y %

X + Y = 100%   OR X = 100% - Y

36.36575 = 34.968853X + 36.965903Y  

36.36575 = 34.968853(1-Y) + 36.936.96590365903Y

36.36575 = 34.968853 -34.968853Y + 36.965903Y

1.396897 = 1.99705Y

Y = 0.699 = 69.95%

X = 100-69.9 = 30.05%

To control, we can plug in the following equation:

34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658

This means

37Cl ⇒ 36.965903 amu  has an abundance of 69.95 %

35Cl ⇒ 34.968853 amu  has an abundance of 30.05%

7 0
3 years ago
A sample of n2 effuses in 255 s. how long will the same size sample of cl2 take to effuse?
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R₁/R₂ = √(M₂/M₁)

Let 1 be N₂ while 2 be Cl₂

255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s

<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
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Answer:

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5 0
1 year ago
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