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3 years ago

11

Write a real world problem to represent an inequality, write an inequality, and solve the problem. Show your work for full credi

t.

1 answer:

Annette [7]3 years ago

7 0

Answer:

20,000 + 12,000 + c ≤ 65,000

20,000 + 12,000 + c – 32,000 ≤ 65,000 – 32,000

c ≤ 33,000

Step-by-step explanation:

cab weight + trailer weight + cargo weight ≤ allowable weight

20,000 + 12000 + c ≤ 65000

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Mrs. Galicia has a cupcake company. The amount of money earned is represented by

sashaice [31]

Using the profit function, it is found that:

a) She earns $36 after 25 years.

b) The function was shifted right 4 units and up 1 units.

<h3>What is the profit function?</h3>

The profit, in x years after 2015, is given by:

$p(x) = 12\sqrt[3]{x + 2}$

Item a:

She earns $36 after x years, considering x for which p(x) = 36, hence:

$p(x) = 12\sqrt[3]{x + 2}$

$36 = 12\sqrt[3]{x + 2}$

$\sqrt[3]{x + 2} = 3$

$(\sqrt[3]{x + 2})^3 = 3^3$

$x + 2 = 27$

$x = 25$

She earns $36 after 25 years.

Item b:

The new function is:

$h(x) = 12\sqrt[3]{x - 2} + 1$

At the domain, we have that $x + 2 \rightarrow x - 2$ , that is, $x \rightarrow x - 4$ , hence it was shifted right 4 units.

At the range, we have that $h(x) = h(x - 4) + 1$ , hence it was shifted up 1 unit.

You can learn more about functions at brainly.com/question/24380382

6 0

2 years ago

An auditorium has 80 rows of seats and the number of seats per row increases at a constant rate. If there are 32 seats in the 8t

expeople1 [14]

To find how many seats in the 80th row, you need to figure out the pattern from the 8th row to the 20th row.

To do this, you can create a table showing possibilities from the 8th to the 20th.

I started with 32 at the 8th and added 2 each time. This was only 56 by the 20th.

Then I added 3, and this got me to 68 by the 20th row.

Then you can work backwards to find how many seats in the 1st row. I got 11.

From here you can create an equation that you could use to solve for the 80th row.

11 + 3(r - 1), where r is the number of rows.

Substitute in 80 for r.

11 + 3(80 - 1)
11 + 237
248 seats

There are 248 seats in the 80th row.

4 0

3 years ago

PLEASE HELP!!! CALCULUS ASSIGNMENT

Serga [27]

Answer:

(d) $\displaystyle 12x^3 - 15x^2 + 2$

General Formulas and Concepts:

<u>Algebra I</u>

Functions
Function Notation

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle y = 3x^4 - 5x^3 + 2x - 1$

<u>Step 2: Differentiate</u>

Basic Power Rule: $\displaystyle y' = 4(3x^{4 - 1}) - 3(5x^{3 - 1}) + 2x^{1 - 1} - 0$
Simplify: $\displaystyle y' = 4(3x^3) - 3(5x^2) + 2$
Multiply: $\displaystyle y' = 12x^3 - 15x^2 + 2$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

3 0

3 years ago

Read 2 more answers

From the passage best

damaskus [11]

Answer:20 + 35 *x=y

Step-by-step explanation:

4 0

3 years ago

115. Sami opens an account and deposits $100 into it at the end of each month. The account earns 2% per year compounded monthly.

givi [52]

Step-by-step explanation:

Geometric series.

Month 3.

100(1+\frac{0.02}{12})^2 + 100(1+\frac{0.02}{12})+100

Month 4.

100( 1 + \frac{0.02}{12})^3 + 100( 1 + \frac{0.02}{12})^2+100(1+\frac{0.02}{12})+100

Month 5.

100(1 + \frac{0.02}{12})^4 + 100(1 + \frac{0.02}{12})^3 + 100(1 + \frac{0.02}{12})^2 +100( 1 + \frac{0.02}{12}) + 100

4 0

4 years ago