Answer:
<em>A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. </em>
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Explanation:
If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.
Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner
well it would be A because 55 degrees is going strait well 75 is going literally straight up
Answer:
L = μ₀ n r / 2I
Explanation:
This exercise we must relate several equations, let's start writing the voltage in a coil
= - L dI / dt
Let's use Faraday's law
E = - d Ф_B / dt
in the case of the coil this voltage is the same, so we can equal the two relationships
- d Ф_B / dt = - L dI / dt
The magnetic flux is the sum of the flux in each turn, if there are n turns in the coil
n d Ф_B = L dI
we can remove the differentials
n Ф_B = L I
magnetic flux is defined by
Ф_B = B . A
in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product
n B A = L I
the loop area is
A = π R²
we substitute
n B π R² = L I (1)
To find the magnetic field in the coil let's use Ampere's law
∫ B. ds = μ₀ I
where B is the magnetic field and s is the current circulation, in the coil the current circulates along the length of the coil
s = 2π R
we solve
B 2ππ R = μ₀ I
B = μ₀ I / 2πR
we substitute in
n ( μ₀ I / 2πR) π R² = L I
n μ₀ R / 2 = L I
L = μ₀ n r / 2I
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3
Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3
Then, the answer is the option C.
The answer is 100.
The formula is KE = 1/2mv^2
Then you plug in 50 to the m
And 2 to the v . That’s how I got 100 .
Hope this helps
