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Scorpion4ik [409]
3 years ago
15

The stoplights on a street are designed to keep traffic moving at 24 mi/h. The average length of a street block between traffic

lights is about 80 m. What must be the time delay between green lights on successive blocks to keep the traffic moving continuously? There are 1.609 × 103 m in a mile. Answer in units of s.
Physics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

t = 7.5 s

Explanation:

As we know that the average speed between two lights is given as

v = 24 mph

here we know that

v = 24 \times \frac{1602 m}{3600 s}

v = 10.68 m/s

now the distance between two lights is 80 m

so here if all the cars are moving continuously between two lights then the time delay between two lights is given as

t = \frac{L}{v}

t = \frac{80}{10.68}

t = 7.5 s

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Physics is explicitly involved in studying which of these activities?
Dmitrij [34]
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The answer to this question would be C
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8 0
3 years ago
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As gravity continues to crush the inner core, the fusion of carbon and oxygen begins. What temperature is needed for the fusion
Olin [163]

Answer:

600,000,000 degree C

Explanation:

This stage is the last stage and is refereed to as supernova. In the beginning of this stage, gravity pulls the inner core and crush it, due to which fusion of atoms starts. Carbon and Oxygen fuse together and the temperature is about of 600,000,000 degree C.

The most heavier atom that can be formed out of this fusion is the iron. The moment all the atoms becomes of iron, no further fusion is possible hence that body emits radiation of high intensity and collapse causing a big supernova.

8 0
2 years ago
NEED HELP ASAPTsunamis are often called tidal waves because they are caused by tides.
garik1379 [7]

Answer:

false

Explanation:

a tsunami is almost always caused by an earthquake under water.

5 0
2 years ago
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The
Reika [66]

Complete question:

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The

particle is momentarily at rest at t is:

Select one:

a. 9.3s

b. 1.3s

C. 0.75s

d.5.3s

e. 7.3s

​

Answer:

b. 1.3 s

Explanation:

Given;

position of the particle, x(t)=1 6t- 3.0t³

when the particle is at rest, the velocity is zero.

velocity = dx/dt

dx /dt = 16 - 9t²

16 - 9t² = 0

9t² = 16

t² = 16 /9

t = √(16 / 9)

t = 4/3

t = 1.3 s

Therefore, the particle is momentarily at rest at t = 1.3 s

6 0
3 years ago
A projectile enters a resisting medium at x = 0 with an initial velocity v0 = 910 ft/s and travels 5 in. before coming to rest.
evablogger [386]

Answer:

a = - 1.987 × 10⁶ ft/s²

t = 6.84 × 10⁻⁴ s

Explanation:

v₀ = 910 ft/s

x = 5 in.

relation v = v₀ - k x

v = 0 as body comes to rest

0 = 900 - 5k/12

k = 2184 s⁻¹

acceleration

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

where

(A) a = -k × v

 at v= 910 ft/s

     a = - 1.987 × 10⁶ ft/s²

(B)  at x = 3.9 in.

v = 910 - 3.9(2184)/12

v = 200.2 m/s

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{dv}{v} = -kdt

\int\limits^{200.2}_{900} {\frac{1}{v} }dv = -k\int\limits^t_0 dt

ln(200.2)-ln(900) = -kt

t = 6.84 × 10⁻⁴ s

3 0
2 years ago
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