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masya89 [10]
3 years ago
9

What is the current if a charge of 25 coulombs passes in 5 seconds?

Physics
1 answer:
Jobisdone [24]3 years ago
8 0

Answer: 5 amps

Explanation: I = Q/t

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gold has a density of 19.32g/cm^3. aluminum has a density of 2.7g/cm^3. which is heavier: 1g of gold or 1 g of aluminum? explain
DENIUS [597]
Gold is much heavier because it has a greater density, meaning the atoms are more closely packed. Also, the individual atoms are heavy as well making 1g of gold heavier than 1g of aluminum.
6 0
3 years ago
Tim jogs a distance of 7.2 km to the west. Then he turns south and jogs 1.4 km. West is the resultant if Tim's jog back to the b
vesna_86 [32]

Answer:

Explanation:

If Tim jogs a distance of 7.2 km to the west and then he turns south and jogs 1.4 km, the resultant displacement of Tim is calculated using the pythagoras theorem as shown;

R² = 7.2²+1.4²

R² = 51.84+1.96

R² = 53.8

R = √53.8

R = 7.33 km

Hence  the resultant of Tim's jog back to the beginning is 7.33km

3 0
4 years ago
An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work
amid [387]

Answer:

Its  answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

6 0
3 years ago
Before light can undergo total internal reflection when incident on material 2 from material one, what must be true
otez555 [7]

Uh i think you need to show me the material one and material 2?

7 0
2 years ago
Two point charges exert a 7.35 N force on each other. What will the force become if the distance between them is increased by a
I am Lyosha [343]

Answer :

New force becomes, F' = 1.83 N

Explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

q_1\ and\ q_2 are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

F'=\dfrac{kq^2}{r'^2}

F'=\dfrac{kq^2}{(2r)^2}

F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}

F'=\dfrac{1}{4}\times 7.35

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.          

3 0
3 years ago
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