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marta [7]
3 years ago
15

Image "B" shows more biodiversity than image "A". Why?

Chemistry
1 answer:
Ilya [14]3 years ago
8 0

Answer:

The answer is A

Explanation:

Image A has the same species while image B has more species than A.

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Which of the following is referenced in the modern "periodic law"
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Atomic number is correct
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Veins carry what type of blood from all the parts of the body back to the heart
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Answer:

The veins (blue) take oxygen-poor blood back to the heart. Arteries begin with the aorta, the large artery leaving the heart. They carry oxygen-rich blood away from the heart to all of the body's tissues.

Explanation:

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What happens when a solid is dissolved into a liquid?
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the solid particles breaks down allowing the liquid to mix with

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What is the ph of 0.51 m ca(ch3coo)2 solution?
Sidana [21]

Answer : The pH of calcium acetate solution will be 9.38.


Explanation : When calcium acetate dissocates completely in solution to form Calcium(+2) ions and two acetate ions, this gives the acetate ion concentration as (2 X 0.51 M) = 1.02 M

Acetate ion then hydrolyzes as follows;


C_{2}H_{3}O_{2}^{-}  + HOH  HC_{2}H_{2}O_{2} + OH^{-}:

Now, Kb will be = [HC_{2}H_{2}O_{2}]  [OH^{-}] / [C_{2}H_{3}O_{2}^{-}]


= Kw / Ka


= 1 x 10^{-14} / 1.8 x 10^{-5} = 5.6 × 10^{-10}

[OH^{-}] = 2.4 × 10^{-5}


Now, we know , pOH = -log [OH^{-}] = 4.62


So, the pH = 14 - pOH = 14 - 4.62 = 9.38

8 0
3 years ago
1. Perform calculations to determine the amount of 6.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-5 M dye solu
zhannawk [14.2K]

Answer:

1a. 6.70 ml of stock dye solution is required

1b. 10.0 ml of stock dye solution is required

1c. 4.00 ml of stock dye solution is required

Explanation:

1a. Using m₁v₁ = m₂v

6.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁵

v₁ = 4 * 10⁻⁴/6.00 * 10⁻⁵

v₁ = 6.70 mL of stock solution

Therefore, 6.70 ml of stock dye solution is required

b. Using m₁v₁ = m₂v

2.00 * 10⁻⁵ * v₁ = 20.0 * 1.00 * 10⁻⁵

v₁ = 2 * 10⁻⁴/2.00 * 10⁻⁵

v₁ = 10.0 mL of stock solution

Therefore, 10.0 ml of stock dye solution is required

c. Using m₁v₁ = m₂v

1.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁶

v₁ = 4 * 10⁻⁵/1.00 * 10⁻⁵

v₁ = 4.00 mL of stock solution

Therefore, 4.00 ml of stock dye solution is required

The procedure is then followed as in steps 2 to 4.

4 0
3 years ago
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