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lesya692 [45]
3 years ago
13

Find the wavelength of light which is capable of ionizing a hydrogen atom?

Physics
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

The correct answer is -  91.4 nm

Explanation:

According to Bohr's model, the minimum wavelength to ionize Hydrogen atom from n= 1 state is expressed as:

(h×c)/λ=13.6eV

here,

h - Planck constant

c - the speed of light

λ - wavelength

Placing the value in the formula for the wavelength

(6.626×10^−34J.s × 3×10^8 m/s)/λ  =  13.6 ×1.6 × 10^−19 J

λ≈91.4nm

Thus, the correct answer would be = 91.4 nm

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Because of friction...
tatuchka [14]

Answer:

<h3>Because of friction , B. not all potential energy is converted into kinetic energy.</h3>

l hope it helps

3 0
3 years ago
Read 2 more answers
Hello, please anybody help if you can!!
Vinil7 [7]
This is called "projectile motion".  The projectile can be a baseball,
a bullet, a golf ball, or a rock that somebody tossed.  In this story, 
the swimmer is the projectile.

In projectile motion, the projectile is moving part horizontally and part
vertically at the same time.  The thing to remember about this kind of
motion is:  The horizontal motion doesn't change, but the vertical motion
changes because of gravity ... just like an apple that fell from a tree.

The swimmer runs straight horizontally off the diving board.  His horizontal speed is 3.62 m/s.  He hits the water  1.68 m from the end of the board.  How long did it take him to go that far ?

       Time  =  (distance) / (speed)

                 =  (1.68 m) / (3.62 m/s)

                 =  (1.68 / 3.62)  seconds

                 =          0.464 second .

(a).
How high above the water was the diving board ?
Well, the swimmer was falling for 0.464 second .
The height is whatever it takes 0.464 second to fall.

           Height  = (1/2) x (acceleration of gravity) x (time)²

                        = (1/2) x      (9.8 m/s²)                  x (0.464 sec)²

                        =        (4.9 m/s²)                x             (0.2153 sec²)

                        =              (4.9  x  0.2153)     meters

                        =                    1.055  meters .  

(b). 
If the swimmer runs off the board slower, his horizontal speed is
lower.  That only affects how far out in front of the board he'll be
when he hits the water.  But his horizontal speed has no effect
on how long it takes him to fall to the water.  That's his vertical
speed, and it only depends on gravity. 
No matter how fast or slow he runs off the board, or if he just
stands there at the end and leans over until he falls, it takes him
the same time to reach the water in every case.
6 0
3 years ago
Two points are on a disk turning at constant angular velocity. One point is on the rim and the other halfway between the rim and
DerKrebs [107]

Answer:

The point on the rim

Explanation:

All the points on the disk travels at the same angular speed \omega, since they cover the same angular displacement in the same time. Instead, the tangential speed of a point on the disk is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the point from the centre of the disk

As we can see, the tangential speed is directly proportional to the distance from the centre: so the point on the rim, having a larger r than the point halway between the rim and the axis, will have a larger tangential speed, and therefore will travel a greater distance in a given time.

3 0
4 years ago
Please help i need help i’ll give lots of points
N76 [4]

Answer:

OK so ik this but what is you question?

Explanation:

8 0
3 years ago
Read 2 more answers
An ideal spring obeys Hooke’s law, F~ = −k~x. A mass of 0.50 kilogram hung vertically from this spring stretches the spring 0.07
masha68 [24]

The spring constant is 66.7 N/m

Explanation:

First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:

F=mg

where:

m = 0.50 kg is the mass of the object

g=10 m/s^2 is the acceleration of gravity

Substituting,

F=(0.50)(10)=5 N

Now we can use Hookes' law to find the constant of the spring:

F=-kx

where

F is the force applied

k is the spring constant

x is the stretching of the spring

Here we have:

F = 5 N

While the stretching is

x = 0.075 m

Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:

k=\frac{F}{x}=\frac{5}{0.075}=66.7 N/m

#LearnwithBrainly

5 0
3 years ago
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