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3 years ago

Please help i need help i’ll give lots of points

Physics

2 answers:

N76 [4]3 years ago

8 0

Answer:

OK so ik this but what is you question?

Explanation:

erma4kov [3.2K]3 years ago

3 0

Answer:

whats the question first

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Carbon is the main chemical that helped make the first life forms on earth and the life forms were ameba

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4 years ago

An electron moves along the z-axis with vz=4.1Ã107m/s. As it passes the origin, what are the strength and direction of the magne

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Answer:

The value of magnetic field is $B_a=6.56*10^{-19} T$

In the direction of the positive x - axis

The value of magnetic field is $B_a=6.56*10^{-19} T$

In the direction of the positive z - axis

Explanation:

From the question we are told that

The velocity of the electron is $v_z = 4.1*10^{7}m/s$

Considering the first position

The equation for the magnetic field is

$\= B = \frac{\mu_0}{ 4 \pi} \frac{q \=v * \= r}{r^2}$

Now $r = \sqrt{i^2 + j^2 + k^2}$

substituting values

$r = \sqrt{1^2 +0^2 +0^2}$

$= 1$

$\= r = \frac{\r r}{r}$

$\r r = 1 i + 0j + 0k$

Therefore $\= r = \frac{1i + 0j + 0k}{1}$

$= i$

So Substituting $4 \pi *10^ {-7}$ for $\mu_o$ , $1.602 *10^{-19}$ for q

$\= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * i}{1^2}$

$\= B_a=6.56*10^{-19} T (i)$

Considering the second position

Here

$r = \sqrt{0^2 + 0^2 + 2^2}$

$=2$

$\= r = \frac{\r r}{r}$

$\r r = 0 i + 0j + 2k$

$\= r = \frac{0i + 0j + 2k}{2}$

$= k$

So Substituting $4 \pi *10^ {-7}$ for $\mu_o$ , $1.602 *10^{-19}$ for q

$\= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * k}{1^2}$

$\= B_a=6.56*10^{-19} T (k)$

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4 years ago

Why is carbon said to provide a “backbone” in many molecules?(1 point)

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Answer:

The carbon atom has unique properties that allow it to form covalent bonds to as many as four different atoms, making this versatile element ideal to serve as the basic structural component, or “backbone,” of the macromolecules.

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3 years ago

A sports car engine delivers 150 kW to the driveshaft with a thermal efficiency of 20%. The fuel has a heating value of 35 000 k

Andreyy89

Answer:600 kW

Explanation:

Given

Power delivered $P=150 kW$

Fuel heating value $q=35,000 kJ/kg$

thermal Efficiency $\eta =\frac{Power}{Heat}$

$0.2=\frac{150}{35,000\times \dot{m}}$

where, $\dot{m} =mass\ flow\ rate\ of\ fuel$

$\dot{m}=\frac{150}{35,000\times 0.2}$

$\dot{m}=0.0214 kg/s$

For an Engine

$q\dot{m}=P+Q_r , where Q_r=heat\ rejected$

$Q_r=q\dot{m}-P$

$Q_r=750-150=600 kW$

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3 years ago

A man can throw a ball a maximum horizontal distance of 56.1523 m. The acceleration of gravity is 9.8 m/s 2 . How far can he thr

IceJOKER [234]

Answer:

hmax= 28.2 m

Explanation:

Horizontal movement:

For the horizontal movement, as once released, nothing exerts any influence on the ball in the horizontal direction, it will keep moving at a constant speed, so, the equation for the horizontal displacement is as follows:

x = v₀*t = 56.1523 m

Vertical movement:

For the vertical movement, once thrown upward, the ball is under the sole influence of gravity, g, which causes the ball to accelerate downward, and which magnitude is 9.8 m/s².
At any time, applying the definition of acceleration, we can find the value of the velocity, as follows:

$vf = vo-g*t$

When the ball reaches to the maximum height, the ball will come momentarily at rest, so vf =0.
At this point, we can find the time at which the ball reached to its highest point, as follows:

$t = \frac{vo}{g}$

In the same way, we can find the maximum height reached by the ball, just replacing this value of time in the equation for the displacement, in the vertical direction, as follows:

$h = vo*t -\frac{1}{2} *g*t^{2}$

$hmax = vo*(\frac{vo}{g}) -\frac{1}{2} *g*(\frac{vo}{g} )^{2} =\frac{vo^{2}}{2*g}$

Now, returning to the horizontal movement, as the time must be the same for both movements, we can replace the value for time we have just found, in the equation for the horizontal displacement:

$x = v0x * t = v0x* \frac{voy}{g}$

But as we know that vox = voy, we can rewrite the equation above as follows:

$x = v0* t = v0* \frac{vo}{g} =\frac{vo^{2} }{g} = 56.1523 m$

We can solve for v₀, as follows:

$vo = \sqrt{56.1523 m *9.8 m/s2} =23.5 m/s$

Now, we can replace this value in the expression for hmax, as follows:
$hmax = \frac{vo^{2}}{2*g} =\frac{(23.5m/s)^{2}}{2*9.8 m/s2} = 28.2 m$

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3 years ago