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Delicious77 [7]
2 years ago
6

Please help i need help i’ll give lots of points

Physics
2 answers:
N76 [4]2 years ago
8 0

Answer:

OK so ik this but what is you question?

Explanation:

erma4kov [3.2K]2 years ago
3 0

Answer:

whats the question first

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Which of the following statements are true? I. The number of protons in an element is the same for all neutral atoms of that ele
FromTheMoon [43]

Answer:

Both statements I, and II are true

Explanation:

I)One is true.The number of protons of the element is the defining characteristic of it. This is, if we take a proton or add a proton to a nucleus we will be changing the element. Therefore, the number of protons is the same for all neutral and not neutral atoms of that element.

II)Two is true. If an atom is neutral, it will have the same number of electrons and protons. As the number of protons for an element cannot change (see I), then the number of electrons will be the same for all neutral atoms of this element.

III)Three is false. We can have a neutral atoms of the same element with different number of neutrons, as neutrons do not change the charge of the atom(they change their mass, though). These are called Isotopes.

6 0
3 years ago
What is threshold frequency
spayn [35]
Threshhold frequency is defined as the minimum light frequency necessary to start photo-electric emission from the surface. This frequency is just effecient enough to emit electrons without any additional force or energy. this minimum frequency creates the necessary result that is sought by the person. The photo electric emission for certain metals can occir with threshhold frequency. The importance of this threshhold frequency lies in the fact that this has been used to create numerous instruments like amplifiers for use of people.
3 0
3 years ago
Read 2 more answers
What are AR,L,K in the periodic table
Scilla [17]

Answer:

Argon, Lithium and Potassium

Explanation:

7 0
3 years ago
Read 2 more answers
3.
weeeeeb [17]

Answer:

I.72m/s²

II.8m/s²

Explanation:

acceleration equal velocity² divided by length

8 0
2 years ago
A mass m at the end of a spring oscillates with a frequency of 0.89 hz. when an additional 603 g mass is added to m, the frequen
MrMuchimi

The solution for this problem:

Given:

f1 = 0.89 Hz

f2 = 0.63 Hz

Δm = m2 - m1 = 0.603 kg 


The frequency of mass-spring oscillation is: 
f = (1/2π)√(k/m) 
k = m(2πf)² 

Then we know that k is constant for both trials, we have: 
k = k 


m1(2πf1)² = m2(2πf2)² 

m1 = m2(f2/f1)² 


m1 = (m1+Δm)(f2/f1)² 


m1 = Δm/((f1/f2)²-1)

 m 1 = 0.603/ (0.89/0.63)^2 – 1

= 0.609 kg or 0.61kg or 610 g

5 0
3 years ago
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