Answer:
1.65 m
Explanation:
The motion of the ball is a projectile motion, so it is a parabolic motion with two independent motions:
- on the x-axis, a uniform motion with constant speed 
- on the y-axis, a uniformly accelerated motion with constant acceleration 
downward.
First of all, we need to find the time t at which the ball has travelled halfway to the chatcher, i.e. at a distance of 
. This can be found by using the relationship between distance, time and velocity along the horizontal direction:
So now we can move to the vertical motion, and we can calculate the distance covered vertically by the ball while falling for t=0.58 s, by using:
Two resistor of 2Ω in series parallel to resistor 5Ω in series to a 2Ω resistor. This configuration gives to us an equivalent resistor of 2.55Ω.
To solve this problem we have to use the rules of conection of resistor in series and parallel.
A resistor R1 in serie with other resistor R2 gives us an equivalent resistor Req= R1 + R2.
A resistor R1 in parallel with other resistor R2 gives us an equivalent resistor Req = R1.R2/R1+R2.
The circuit that show an arregement of resistor which we obtain a equivalent resistor of 2.5Ω from three resistor of 2Ω and 5Ω respectively is attached in the image:
Answer:
a) F₁ = F₂, F₃ = F₄, b) the correct answer is 3
Explanation:
a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies
Forces 1 and 2 are action and reaction forces F₁ = F₂
Forces 3 and 4 are action and reaction forces F₃ = F₄
as it indicates that the
b) how the car increases if speed implies that force 1> force3
F₁ > F₃
therefore the correct answer is 3
To calculate that, we'd need to know the coefficient of static friction between the block and the surface, which you haven't told us.
P=mv
pi =pf
(68x2.79)+(131x0) = 199v
v= 0.95 m/s
