Explanation:
Le Chatelier's principle states that for a long period of time if a system is at equilibrium and it is subjected to change in concentration, temperature, volume or pressure then the system shifts to a new equilibrium.
This change will partly counter acts the applied change.
Therefore, when heat is added to the system then equilibrium will shift to the side where temperature or heat is reduced again.
For example, 
Since heat is added to the system, hence, system will shift to the left side or we can say equilibrium will shift to the backward direction.
Answer:
1. Hydrogen will diffuse faster.
2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1
Explanation:
Let the rate of diffusion of hydrogen gas, H2 be R1
Let the molar mass of H2 be M1
Let the rate of diffusion of the unknown gas be R2.
Let the molar mass of the unknown gas be M2.
Molar mass of H2 (M1) = 2x1 =2g/mol
Molar mass of unknown gas (M2) = 16 times that of H2
= 16 x 2 = 32g/mol
1. Determination of the gas that will diffuse faster. This is illustrated below:
R1/R2 = √(M2/M1)
R1/R2 = √(32/2)
R1/R2 = √16
R1/R2 = 4
Cross multiply
R1 = 4R2
From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).
Therefore, hydrogen will diffuse faster.
2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;
R1/R2 = 4
Therefore, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is:
4 : 1
Answer:
like the others its C
Explanation:
the dad has horns but the mom does not so the babys could or they could not
Answer:
increasing the separation distance between objects decreases the force of attraction
Explanation:
Answer:
Molarity = moles / volume
moles of HCl = molarity ×volume
= 0.0150 M × 0.08189L
= 0.0123mol
∴ the amount of CaCO3 neutralized by 0.0123 mole of HCl will be in 1:2 ratio.
moles of CaCO3 = 0.0123 mol of HCl× 1mol CaCO3/ 2mol HCl
= 0 .00614 mol
∴ the tablet has 0.00614 mol of CaCO3.
Explanation:
Step 1:
In the above-experiment problem, HCl acid solution is basically treated with CaCO3 base active in the tablet.
The mass of CaCO3 present in the tablet must be obtained in milligram (mg).
First, write down the balanced reaction between HCl and CaCO3
2Hcl aq + CaC03 s ⇒ CaCl2 aq + H2O l + C02 g
CaCO3 and HCl react in 1:2 ratio of moles respectively.
∴ for each mole of calcium carbonate there would be twice the moles of HCl required for neutralization.
Step 2
the volume is 81.89 mL (i.e 0.08189 L) of 0.150 M HCl neutralizes the whole tablet containing unknown amount of CaCO3.
So, the number of moles of HCl present in the taken volume is calculated
