(Three-fourths x minus two-thirds) minus (Negative StartFraction 5 over 6 EndFraction + 2 x)?

Mathematics

2 answers:

Alex73 [517]3 years ago

8 0

Answer:

the answer is A

Step-by-step explanation:

i got the wrong and found that the anwer is A

Shkiper50 [21]3 years ago

6 0

Answer:

$\frac{1}{6}-1\frac{1}{4}x$

Step-by-step explanation:

Given $(\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)$

#We can evaluate by removing brackets and grouping the like terms:

$=(\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)\\\\=\frac{3}{4}x-\frac{2}{3}+\frac{5}{6}-2x\\\\=\frac{1}{6}-1\frac{1}{4}x$

Hence, the given problem can be solved to it's simplest form as $\frac{1}{6}-1\frac{1}{4}x$

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Graph the exponential model y=3(6)^x Which point lies on the graph? (-9 2) (-1, -18) (1, 18) (2, 9)

svetlana [45]

Answer:

(1,18)

Step-by-step explanation:

use a graphing calculator to graph the function

then, graph all the coordinates given and find on that's on the graph

7 0

3 years ago

Hey guys I need your help on this!!

kogti [31]

Answer:

Domain: (-∞, ∞) or All Real Numbers

Range: (0, ∞)

Asymptote: y = 0

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞

Step-by-step explanation:

The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.

The range is from 0 to ∞. This where all values of y are defined.

An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.

The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞