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kompoz [17]
3 years ago
10

(Three-fourths x minus two-thirds) minus (Negative StartFraction 5 over 6 EndFraction + 2 x)?

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

the answer is A

Step-by-step explanation:

i got the  wrong and found that the anwer is A

Shkiper50 [21]3 years ago
6 0

Answer:

\frac{1}{6}-1\frac{1}{4}x

Step-by-step explanation:

Given (\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)

#We can evaluate by removing brackets and grouping the like terms:

=(\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)\\\\=\frac{3}{4}x-\frac{2}{3}+\frac{5}{6}-2x\\\\=\frac{1}{6}-1\frac{1}{4}x

Hence, the given problem can be solved to it's simplest form as \frac{1}{6}-1\frac{1}{4}x

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PLSSS HELP ASAP<br> solve questions 1-5 please
sertanlavr [38]

#1. 4x^2 + 17 - 15 = 0

Use the roots given, and plug them in to a factored form. Then, foil! It can also be helpful to multiply the equation to get rid of decimals/fractions.

(x - 3/4)(x + 5) = 0

x^2 - 3/4x + 5x - 3 3/4 = 0

x^2 + 4.25 - 3.75 = 0 (multiply everything by 4)

4x^2 + 17 - 15 = 0

#2. y = 0, -4

Both 4y^2 and 16y contain a 4 in the coefficient and a y in the variables. Therefore, we can factor out a 4y from each.

4y(y + 4) = 0

Then, set both parts of the factored equation equal to 0.

4y = 0

y = 0

y + 4 = 0

y = -4

#3. a = 0, -3

Both 6a^5 and 18a^4 contain a 6 in the coefficient and an a in the variables. Therefore, we can factor out a 6a^4 from each.

6a^4(a + 3) = 0

Then, set both parts of the factored equation equal to 0.

6a^4 = 0

a = 0

a + 3 = 0

a = -3

#4. x = -8

We are looking for two terms that multiply to equal a * c, and add up to equal b. We know that 8 + 8 = 16, and 8 * 8 = 64. There are no negatives in this equation, therefore both signs in our factored form are positive.

(x + 8)(x + 8) = 0

x + 8 = 0

x = -8

#5. x = -8, 8

First, subtract 64 from both sides. The key word here is 'factoring.' If this was not present, there is a different way (which may be easier for some).

x^2 = 64

x^2 - 64 = 0

Next, use the difference of two squares property to factor (x - c)(x + c), and set the two binomials equal to 0.

(x - 8)(x + 8) = 0

x - 8 = 0

x = 8

x + 8 = 0

x = -8

Hope this helps!! :)

3 0
3 years ago
The graph of Fx) can be compressed vertically and shifted to the right to
MrMuchimi
Idk what it is tbh i can’t with math
7 0
4 years ago
0.09859154929 round to nearest tenth
Free_Kalibri [48]

Answer:

0.1

Step-by-step explanation:

5 0
3 years ago
Suppose a football player kicks a ball and gives it an initial upward velocity of 47 ft/s. Use the formula h(t)= -16t^2+47t+3 wh
statuscvo [17]

Answer:

Step-by-step explanation:

a. when t=0,h=3ft

h(t)=-16 (t^2-\frac{47}{16}x+(\frac{47}{32} )^2)+\frac{47^2}{32^2} *16+3\\=-16(t-\frac{47}{32})^2+\frac{2209}{64}+3\\=-16(t-\frac{47}{32})^2+\frac{2209+192}{64}\\when~ t=\frac{47}{32}\\h=\frac{2301}{64}\\or~v^2-u^2=2gh\\\\0^2-47^2=2*(-32)h\\or h=\frac{47^2}{64}=\frac{2209}{64} \\height from the ground=\frac{2209}{64} +3=\frac{2301}{64}

c.t=47/32 sec

d.

time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2

t^2=\frac{2301}{64*16}

t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}

total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec

4 0
3 years ago
Please help me solve these, I tried solving them but I got confused with the signs,
AlekseyPX

Answer:

a) x= -5

b) x= 3

c) x= -5

3 0
3 years ago
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