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kompoz [17]
3 years ago
10

(Three-fourths x minus two-thirds) minus (Negative StartFraction 5 over 6 EndFraction + 2 x)?

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

the answer is A

Step-by-step explanation:

i got the  wrong and found that the anwer is A

Shkiper50 [21]3 years ago
6 0

Answer:

\frac{1}{6}-1\frac{1}{4}x

Step-by-step explanation:

Given (\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)

#We can evaluate by removing brackets and grouping the like terms:

=(\frac{3}{4}x-\frac{2}{3})-(-\frac{5}{6}+2x)\\\\=\frac{3}{4}x-\frac{2}{3}+\frac{5}{6}-2x\\\\=\frac{1}{6}-1\frac{1}{4}x

Hence, the given problem can be solved to it's simplest form as \frac{1}{6}-1\frac{1}{4}x

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What is the surface area
ArbitrLikvidat [17]

Answer:

184 m²

Step-by-step explanation:

Surface Area = 2(10*2) + 2(10*6) + 2(2*6)

Surface Area = 2(20 + 60 + 12)

Surface Area = 2(92)

Surface Area = 184 m²

If my answer is incorrect, pls correct me!

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5 0
3 years ago
Hey can somebody help y+5=2(x+1)
kifflom [539]
If you're looking for the equation, the answer is y=2x-3
3 0
2 years ago
Read 2 more answers
Does Anyone have idea how to solve this problem?
garik1379 [7]
A.

5 * 2 = 10

8 * 2 = 16

10 cm by 16 cm is the new dimensions. Area = 160 sq cm. Perimeter = 52 cm.

B.

5 * 3 = 15

8 * 3 = 24

15 cm by 24 cm is the new dimensions. Area = 360 sq cm. Perimeter = 78 cm.

C.

The areas for the different sized photos both still maintain a ratio of 5:8 cm.
6 0
3 years ago
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Write a function rule that gives a worker’s earnings e(n) for n hours when the worker’s hourly wage is $6.37
aleksandrvk [35]

we are given

worker’s hourly wage is $6.37

number of hours is n

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3 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
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