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anastassius [24]
3 years ago
6

Iron is obtained by reaction of hematite (Fe2O3) with carbon monoxide. From the balanced reaction below, how many grams of iron

is produced when 24.6 mol of hematite is used up in the reaction?
Fe2O3 + 3CO ® 2Fe + 3CO2
Chemistry
1 answer:
laila [671]3 years ago
3 0

Answer: 2755.2 g of Fe will be produced from 24.6 mol of haematite.

Explanation:

The balanced chemical equation is:

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2  

According to stoichiometry :

1 mole of Fe_2O_3 produce = 2 moles of Fe

Thus 24.6 moles of Fe_2O_3 will produce=\frac{2}{1}\times 24.6=49.2moles  of Fe  

Mass of Fe=moles\times {\text {Molar mass}}=49.2moles\times 56g/mol=2755.2g

Thus 2755.2 g of Fe will be produced from 24.6 mol of haematite.

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A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.
amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 60.0 min

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

k=\frac{2.303}{60.0}\log\frac{100g}{75g}

k=4.79\times 10^{-3}\text{ years}^{-1}

Now we have to calculate the half-life of the compound.

k=\frac{0.693}{t_{1/2}}

4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=144.676\text{ years}\approx 145\text{ years}

Therefore, the half-life of the compound is, 145 years.

8 0
4 years ago
How many moles of NaCl are in 2,719 mL of a 6.32 M solution?
Mademuasel [1]

Answer:

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Explanation:

Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

6.32 M=\frac{n}{2.719 L}

n=6.32M\times 2.719 L=17.18 mol

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

6 0
4 years ago
How do Ionic bods form in binary compounds?
Aleks04 [339]

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms and is a type of chemical bond that generates two oppositely charged ions. By losing those electrons, these metals can achieve noble-gas configuration and satisfy the octet rule. ...

Explanation:

6 0
3 years ago
Determine the vapor pressure of a solution at 55 °C that contains 34.2 g NaCl in 375 g of water. The vapor pressure of pure wate
uranmaximum [27]

Answer:

Vapor pressure of solution = 111.98 Torr

Explanation:

Colligative property to apply: Lowering vapor pressure

P° - P' = P° . Xm . i

P°, vapor pressure of pure solvent

P', vapor pressure of solution

Xm, mole fraction of solute

i, Van't Hoff factor.

Let's determine the Xm.

Moles of solute = mass / molar mass → 34.2 g / 58.45 g/mol = 0.585 moles

Moles of solvent = 375 g / 18 g/mol = 20.83 moles

Mole fraction = 0.585 mol / 0.585 mol + 20.83 mol → 0.0273

Let's replace the data in the formula:

118.1 Torr - P' = 118.1 Torr . 0.0273 . 1.9

118.1  Torr - 6.12 Torr = P'

Vapor pressure of solution = 111.98 Torr

8 0
4 years ago
7. How many electrons can be held in the energy level n = 4?
Dahasolnce [82]

Answer:

32 electrons

Explanation:

7 0
3 years ago
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