0.01375 moles of nitric acid (HNO₃) which is the limiting reactant
Explanation:
We have the following chemical reaction:
NaOH + HNO₃ → NaNO₃ + H₂O
Now to determine the number of moles of each reactant we use the following formula:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume (L)
number of moles of NaOH = 0.5 × 0.250 = 0.125 moles
number of moles of HNO₃ = 0.55 × 0.025 = 0.01375 moles
From the chemical reaction we see that 1 mole of NaOH reacts with 1 mole of HNO₃, so 0.125 moles of NaOH will react with 0.125 moles of HNO₃ but we only have 0.01375 moles of HNO₃ available, so the limiting reactant is HNO₃.
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Gets exited and moves at a faster constant speed
Answer:
The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.
Explanation:
...[1]
..[2]
..[3]
The standard enthalpy of formation of ethanoic acid :
..[4]
Using Hess's law to calculate :
2 × [1] + 2 × [2] - [3] = [4]
The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.
