Find the value of x..

Edgar owns 234 shares of Cawh Consolidated Bank, which he bought for $21.38 apiece. Each share pays a yearly dividend of $3.15.

trapecia [35]

Answer: B. The stocks have a yield 6.84 percentage points greater than that of the bonds.

Step-by-step explanation:

Firstly, the yield for stocks will be calculated as:

= return/ investment cost

= $3.15/$ 21.38

= 0.14733395

= 14.73%

The yield for bonds will be calculated as:

= Return/Investment cost

Return = 1,000 x 8.3% = 83

Investment cost = 1,000 x 105.166/100 = 1051.66‬

Yield = 83/1051.66

= 0.07892284

= 7.89%

Then, the difference between the yield will be:

= 14.73% - 7.89%

= 6.84%

Therefore, the stocks have a yield 6.84 percentage points greater than that of the bonds.

8 0

2 years ago

A circular plate has circumference 21.4 inches. What is the area of this plate? Use 3.14 for pi.

Brut [27]

Answer:

The area of this plate is $36.31\ \text{inches}^2$ .

Step-by-step explanation:

We have,

Circumference of a circular plate, C = 21.4 inches

The circumference of a circular shape is given by :

$C=2\pi r$

r is radius of circular shape

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{21.4}{2\times 3.14}\\\\r=3.4\ \text{inches}$

Area of this plate is given by :

$A=\pi r^2\\\\A=\pi (3.4)^2\\\\A=36.31\ \text{inches}^2$

So, the area of this plate is $36.31\ \text{inches}^2$ .

8 0

3 years ago

Pleaseeeeeeeee helppp

Stolb23 [73]

2(x-1)=42
2x-2=42
2x=44
X=22

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

2 years ago

X = 2y - 4<br> 7x + 5y = -66

madreJ [45]

Answer:

Step-by-step explanation:

4 0

2 years ago

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