The mass of argon contained in the cylinder is 9691.47 g
<h3>How to determine the mole of the argon</h3>
- Volume (V) = 43.8 L
- Pressure (P) = 1990 psi = 1990 / 14.7 = 135.37 atm
- Temperature (T) = 24.7 °C = 24.7 + 273 = 297.7 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Number of mole (n) =?
Using the ideal gas equation, the number of mole of the nitrogen oxide can be obtained as follow:
PV = nRT
Divide both side by RT
n = PV / RT
n = (135.37 × 43.8) / (0.0821 × 297.7)
n = 242.59 moles
<h3>How to determine the mass of argon </h3>
- Mole of argon = 242.59 moles
- Molar mass of argon = 39.95 g/mol
- Mass of argon = ?
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of argon = 242.59 × 39.95
Mass of argon = 9691.47 g
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Complete question
A gas cylinder that contains argon has an internal volume of 43.8L A pressure gauge attached to the cylinder reads 1990 psi (1 atm=14.7 psi) at 24.7 Celsius
What mass of argon is contained in the cylinder?
