Answer:
Explanation:
We can use the Ideal Gas Law to calculate the density of the gas.
pV = nRT
n = m/M Substitute for n
pV = (m/M)RT Multiply both sides by M
pVM = mRT Divide both sides by V
pM = (m/V) RT
ρ = m/V Substitute for m/V
pM = ρRT Divide each side by RT
Data:
p = 1.00 bar
M = 49 g/mol
R = 0.083 14 bar·L·K⁻¹mol⁻¹
T = 0 °C = 273.15 K
Calculation:
ρ = (1.00 × 49)/(0.083 14 × 273.15) = 2.2 g/L
The density of the gas is .
H atoms are found in the molecules of covalent compounds that dissolve in water. These compound are called acids (proton donors). They form acidic solutionst{acidic solutions} acidic solutions.
Because there are no ions moving about in solution with covalent molecules, they are characterised as non-electrolytes. Non-electrolyte solutions are those that do not conduct electricity.
Examples are hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid solutions (HNO3).
<h3>
What type of compounds dissociate in water to form ions?</h3>
When certain substances dissolve in water, they undergo either a physical or a chemical change that results in the formation of ions in solution. These substances are members of an important class of compounds known as electrolytes. Nonelectrolytes are substances that do not produce ions when dissolved.
A substance is known as a strong electrolyte if the physical or chemical process that generates the ions is essentially 100% efficient (all of the dissolved compound yields ions). A weak electrolyte is one in which only a small portion of the dissolved substance undergoes the ion-producing process.
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<span>Analytic chemistry because he is comparing to types of refined gasoline. </span>
Answer:
The limiting reactant is B.
Explanation:
The equation for the reaction is given below:
2A + 3B —> C + D
The limiting reactant can be obtained as follow:
From the equation above,
2 units of A reacted with 3 units of B.
Therefore, 5 units of A will react with = (5 x 3) /2 = 7.5 units of B.
From the calculation made above, we can see that it will take a higher unit of B i.e 7.5 units than what was given i.e 6 units to react completely with 5 units of A.
Therefore, B is the limiting reactant and A is the excess reactant.
