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3 years ago

4x^2 - 9y^6 what patterns can be used ? please and thank you !!!

Mathematics

1 answer:

S_A_V [24]3 years ago

3 0

Answer:

B. (U+V)(U-V)

Step-by-step explanation:

Factoring

The given expression is:

$4x^2-9y^6$

It should be noted that both terms are perfect squares:

$(2x)^2=4x^2$

$(3y^3)^2=9y^6$

Since it's a difference of squares, we need to use the following pattern to factor the required expression:

$(U^2-V^2)=(U+V)(U-V)$

Thus, the answer is

B. (U+V)(U-V)

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Answer: 80

Step-by-step explanation: Supplements mean they add up to 180. is m of 3 is 100, then m of 4 must be 80 to add up to 180. Hope this helps!

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3 years ago

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3 years ago

Round down this calculation to Ofe ucci piacer ). Order: Uniphyl (theophylline) 5 mg/kg po loading dose stat. The strength of th

Marta_Voda [28]

Answer:

1 tablet

Step-by-step explanation:

Data provided in the question:

The dose of the Uniphyl = 5 mg/kg

Strength of the Uniphyl = 400 mg per tablet

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Now,

The recommended dose for the patient

= Dose of the Uniphyl × weight of the patient

= 5 mg/kg × 76 kg

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Therefore,

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3 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

Using first principle, this gives:

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

Hence, the smallest sum is 2

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3 years ago

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Step-by-step explanation:

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2 years ago

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