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2 years ago

Soft ball,kick ball,wiffle ball??

Physics

2 answers:

Anvisha [2.4K]2 years ago

6 0

1. No they aren’t because they all belong to different sports and are used differently

Artist 52 [7]2 years ago

5 0

Answer:

1= because they are ball

2= because they are used to play different games

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Coherent light of wavelength 525 nm passes through two thin slits that are 4.15Ã—10^(âˆ’2) mm apart and then falls on a screen 7

IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

$sin \theta=\frac{n \lambda}{d}$

where

n is the order of the maximum

$\lambda$ is the wavelength

$a$ is the distance between the slits

In this problem,

n = 5

$\lambda=525 nm =5.25\cdot 10^{-7} m$

$a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m$

So we find

$\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}$

And given the distance of the screen from the slits,

$D=75.0 cm = 0.75 m$

The distance of the 5th bright fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm$

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

$sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}$

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

$\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}$

And the distance of the 8th dark fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm$

5 0

3 years ago

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance b

yuradex [85]

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

<h3>Newton's law of universal gravitation</h3>

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

F ∝Mm/r²

Removing the proportionality sign,

F = GMm/r².

Where:

F = Force of attraction
G = Gravitational constant
M = Bigger mass
m = Smaller mass
r = Distance between the masses.

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Learn more about Newton's law of universal gravitation here: brainly.com/question/9373839

#SPJ12

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2 years ago

The parking brake on a 1000 kg Cadillac has failed, and it is rolling slowly, at 1 mph , toward a group of small children. Seein

iogann1982 [59]

Answer:

0.5 mph in the opposite direction

Explanation:

$m_1$ = Mass of Cadillac = 1000 kg

$v_1$ = Velocity of Cadillac = 1 mph

$m_2$ = Mass of Volkswagen = 2000 kg

$v_2$ = Velocity of Volkswagen

In order to know the speed the system must have the momentum exchange

As the linear momentum of the system is conserved

$m_1v_1+m_2v_2=0\\\Rightarrow v_2=-\dfrac{m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{1000\times 1}{2000}\\\Rightarrow v_2=-0.5\ mph$

The speed of the impact is given by 0.5 mph in the opposite direction

8 0

3 years ago

Four model rockets are launched in a field. The mass of each rocket and the net force acting on it when it launches are given in

ankoles [38]

Answer:Rocket 2

Explanation:

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2 years ago

The focus of counterinsurgency (coin) operations generally progresses through three stages. which stage concerns itself with exp

posledela

The term counter-insurgency refers to the actions (political and military) that aims in targeting the activities the revolutionaries. This operation consists of three stages. The stage that focuses on the expansion of stability operations onto the opposed regions by utilizing host nation forces belongs to the middle stage. Answer is C.

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3 years ago