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Aneli [31]
4 years ago
14

Le Which describes how light waves can interact with wood?

Physics
1 answer:
DanielleElmas [232]4 years ago
3 0

Answer:

a

Explanation:

cas i know

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In everyday situations, it does seem that a force is needed to keep an object, for example the shopping trolley, moving at a con
Jobisdone [24]

Answer:

Because of friction

Explanation:

7 0
3 years ago
Read 2 more answers
Which of the following terms best describes a conceptual scheme in science that is strongly supported, has not yet been found in
Flauer [41]

Answer:

A) a scientific theory or principle

Explanation:

A Theory or principle has to explain different observations for a specific phenomenon. Theories are tested in base of new data to see if they can fit with all the new variations. They gain more acceptance in the scientific world if they predict in a correct way the result of many observations.

For example the uncertainty principle which state that the position and the momentum of a particle can not be known at the same time. Many experiments that aim to test the Uncertainty principle demonstrated this property, but tests are currently being done with other variations to see if the principle still fits with them.

3 0
4 years ago
6. According to Ohm's Law, current (I), voltage (V), and resistance (R)
SIZIF [17.4K]

Answer: C

Explanation: according to the law voltages = to current and resistance

7 0
3 years ago
How much heat is absorbed by a 66g iron skillet when its temperature rises from 7oC to 20oC?
fenix001 [56]
The heat absorbed is calculated using the following equation:
Q = mCΔT

Q = heat absorbed
m = mass = 66 g
C = specific heat of iron = 0.449 J/g.°C
ΔT = temperature change = 20 - 7 =13°C

Therefore,
Q = 66*0.449*13 = 385.242 J
3 0
3 years ago
According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
NARA [144]

Answer:

Orbital period, T = 1.00074 years

Explanation:

It is given that,

Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

T^2=\sqrt{9.96\times 10^{14}}\ s

T = 31559467.6761 s

T = 1.00074 years

So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.

6 0
3 years ago
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