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3 years ago

What do proteins act as?

1 answer:

8 0

Proteins are made from long chains of smaller molecules called amino acids. These long chains are folded into particular shapes. This is important in relation to how antibodies and enzymes work.

Enzymes are biological catalysts. There are optimum temperatures and pH values at which their activity is greatest. Enzymes are also proteins. If the shape of an enzyme changes, it may no longer work (it is said to have been 'denatured'). maybe right?

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Full complete ion name for HO2?

Oksi-84 [34.3K]

The hydroperoxyl radical, also known as the perhydroxyl radical, is the protonated form of superoxide with the chemical formula HO2. This species plays an important role in the atmosphere and, as a reactive oxygen species, in cell biology

7 0

3 years ago

Using the equations 2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/m

Dafna11 [192]

Answer : The enthalpy for the reaction is 49.1 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $C_6H_6$ will be,

$6C(s)+3H_2(g)\rightarrow C_6H_6(l)$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $2C_6H_6(g)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)$

$\Delta H_1=-6271kJ/mole$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$

$\Delta H_2=-393.5kJ/mole$

(3) $2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$

$\Delta H_3=-483.6kJ/mole$

Now we will reverse the reaction 1 and divide by 2, multiply reaction 2 by 6 and reaction 3 by 3/2 then adding all the equations, we get :

(1) $6CO_2(g)+3H_2O(l)\rightarrow C_6H_6(g)+\frac{15}{2}O_2(g)$

$\Delta H_1=-\frac{-6271kJ/mole}{2}=3135.5kJ/mol$

(2) $6C(s)+6O_2(g)\rightarrow 6CO_2(g)$

$\Delta H_2=6\times (-393.5kJ/mole)=-2361kJ/mol$

(3) $3H_2(g)+\frac{3}{2}O_2(g)\rightarrow 3H_2O(l)$

$\Delta H_3=\farc{3}{2}\times (-483.6kJ/mole)=-725.4kJ/mol$

The expression for enthalpy of formation of $C_6H_6$ will be,

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(3135.5kJ/mole)+(-2361kJ/mole)+(-725.4kJ/mole)$

$\Delta H=49.1kJ/mole$

Therefore, the enthalpy for the reaction is 49.1 kJ/mol

7 0

3 years ago

28.

allochka39001 [22]

Answer: I believe that B) require target cell receptors to illicit a target cell response, is the right answer.

Explanation:

6 0

3 years ago

What property do all of the group 18 elements have that make them stand out from other elements?

matrenka [14]

They are very stable (not reactive).

This is because their outer shell has a total of 8 valence electrons. All elements strive to get towards a full outer shell, but since these elements already have a full outer shell, they are fairly unreactive.

5 0

3 years ago

The value of Avogadro number is

Anastasy [175]

The value of Avogadro number is 6.02214076 × 10^24

6 0

2 years ago