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wlad13 [49]
1 year ago
13

Hello people ~help me with these questions ​

Chemistry
2 answers:
Paraphin [41]1 year ago
8 0

#1

  • The formula is NaHCO_3

If it is mixed with water or aqueous then it forms basic solvent.

#2

Soda lime is a key reagent in purification of organic compounds.

  • Its basic
  • Its the mixture of NaOH and CaO
olganol [36]1 year ago
4 0

  • The aqueous of baking soda is basic.

\\ compound: sodium bicarbonate || NaHCO₃ \\

  • The aqueous solution of soda lime is basic.

\\ compound: CaHNaO₂ || sodium calcium hydrate \\

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What would most likely be included in the “Analysis” section of a lab report?
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The purpose of the analysis section of a lab report is to detail what happened in the lab and what the outcome of the project was as a result of said events.
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List 2 everyday examples for<br> decanting <br> centrifuge <br> filtration
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The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi
Gelneren [198K]

Answer : The normal boiling point of ethanol will be, 348.67K or 75.67^oC

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of ethanol at 30^oC = 98.5 mmHg

P_2 = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

T_1 = temperature of ethanol = 30^oC=273+30=303K

T_2 = normal boiling point of ethanol = ?

\Delta H_{vap} = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})

T_2=348.67K=348.67-273=75.67^oC

Hence, the normal boiling point of ethanol will be, 348.67K or 75.67^oC

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