Answer:
a) 0.13 g = 0.13X0.001 kg = 1.3 X 10⁻⁴ kg
b) 232 Gg = 232 X 1000000 kg = 2.32 X 10⁸ kg
c) 5.23 pm = 5.23 X 10⁻¹² m
d) 86.3 mg = 86.3 X 10⁻⁶Kg = 8.63 X 10⁻⁵Kg
e) 37.6 cm = 37.6 X 10⁻² m = 3.76 X 10⁻¹m
f) 54 = 5.4 X 10¹
g) 1 Ts = 10¹² seconds
h ) 27 ps = 27 X 10⁻¹² s= 2.7 X 10⁻¹¹ s
i) 0.15 mK = 1.5 X10⁻⁴ K
Explanation:
A scientific notation is a representation of any number which is very large or very small. It is simplification of writing a number.
The SI units of
i) weight = Kg
ii) length = meter
iii) time = second
iv) temperature = K
a) 0.13 g = 0.13X0.001 kg = 1.3 X 10⁻⁴ kg
b) 232Gg
1 Gg = 1000000 kg
232 Gg = 232 X 1000000 kg = 2.32 X 10⁸ kg
c) 5.23 pm
1 pm = 10⁻¹² m
5.23 pm = 5.23 X 10⁻¹² m
d) 86.3 mg
1mg = 10⁻⁶Kg
86.3 mg = 86.3 X 10⁻⁶Kg = 8.63 X 10⁻⁵Kg
e) 37.6cm
1 cm = 10⁻² m
37.6 cm = 37.6 X 10⁻² m = 3.76 X 10⁻¹m
f) 54 (no units)
54 = 5.4 X 10¹
g) 1 Ts = 10¹² seconds
h ) 27 ps
1 ps = 10⁻¹² s
27 ps = 27 X 10⁻¹² s= 2.7 X 10⁻¹¹ s
i) 0.15 mK
1mK = 10⁻³ K
0.15 mK = 1.5 X10⁻⁴ K
Answer:
211.47 grams
Explanation:
We need to set up a dimensional analysis to solve this problem by converting from moles to grams.
First, find the molar mass of HCl. Since the molar mass of H (hydrogen) is 1.01 g/mol and the molar mass of Cl (chlorine) is 35.45 g/mol, then the molar mass of HCl is:
1.01 + 35.45 = 36.46 g/mol
We have 5.8 moles of HCl, so multiply by its molar mass:
(5.8 mol) * (36.46 g/mol) = 211.468 ≈ 211.47 g
The answer is thus 211.47 grams.
<em>~ an aesthetics over</em>
Answer:
Explanation:
We can use the Combined Gas Laws to solve this problem
Data
p₁ = 571.2 Torr; p₂ = 400 Torr
V₁ = 3.5 L; V₂ = ?
T₁ = 21.5 °C; T₂ = 6.8 °C
Calculations
(a) Convert the temperatures to kelvins
T₁ = (21.55 + 273.15) K = 294.70 K
T₂ = (6.8 + 273.15) K = 279.95 K
(b) Calculate the new volume
