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Jet001 [13]
2 years ago
11

Water boils at 100°C and turns into steam. Which similarities or differences are there between water in these two states? (1 poi

nt)
The particles will have more space between them and will be moving at higher speeds as steam.

The particles will have more space between them as steam, but they will be moving at the same speed in both states.

The particles will have more space between them as a liquid, but they will be moving at the same speed in both states.

The particles will have more space between them as a liquid, but they will be moving faster as steam.
Physics
1 answer:
photoshop1234 [79]2 years ago
3 0

Answer:

My answer was A not sure if its correct as i am still doing the rest of the questions.

Explanation:

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If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.

5 0
3 years ago
The Franck-Hertz experiment involved shooting electrons into a low-density gas of mercury atoms and observing discrete amounts o
Anuta_ua [19.1K]

Answer:

the final kinetic energy is 0.9eV

Explanation:

To find the kinetic energy of the electron just after the collision with hydrogen atoms you take into account that the energy of the electron in the hydrogen atoms are given by the expression:

E_n=\frac{-13.6eV}{n^2}

you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is

E_{n_2-n_1}=-13.6eV[\frac{1}{n_2^2}-\frac{1}{n_1^2}]\\\\E_{2-1}=-13.6eV[\frac{1}{2^2}-\frac{1}{1}]=-10.2eV

-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is:

E_{k}=11.1eV-10.2eV=0.9eV

6 0
3 years ago
What is the wavelength of a wave that has a frequency of 841 Hz if the speed of the wave is 457 m/s?
Dvinal [7]

Answer:

<h3>The answer is 0.54 m</h3>

Explanation:

The wavelength of a wave can be found by using the formula

\lambda =  \frac{c}{f}  \\

where

c is the velocity

f is the frequency

So we have

\lambda =  \frac{457}{841}  \\  = 0.543400713...

We have the final answer as

<h3>0.54 m</h3>

Hope this helps you

6 0
3 years ago
A lawnmower engine running for 20 minutes does 4560000 j of work. What is the power output of the engine
Alenkasestr [34]

<em>Answer: </em>

tim e (t) = 20 min.

            = 20 × 60 = 1200 s ,

Work ( W) = 4560000 J

                 = 4560 KJ ,

Determine:

                 Power output (P) = Work ÷ time

                                              = 4560 ÷  1200

                                         <em>   P  = 3.8 KW</em>


3 0
3 years ago
What quantity measures the number of complete cycles oscillation makes per second?
kirza4 [7]
The answer is (C) Frequency
3 0
3 years ago
Read 2 more answers
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