A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte
rn on a screen 60.0 cm from the slits, and measures the distance between the first and tenth maxima to one side of the central bright spot to be 17.0 mm. What is the wavelength of the light that was used in the experiment?
1 answer:
You might be interested in
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
, and where the negative sign means it points downwards, against the direction of the motion.
Therefore, we can use the following formula to solve the problem:
where
is the initial vertical velocity of the athlete, 
is the vertical velocity of the athlete at the maximum height (and 
at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
Therefore, we can use the following formula to solve the problem:
where
Answer:
The value of is
.
Explanation:
Given that,
Number
Energy difference = 6\times10^{-21}\ J[/tex]
Temperature T =300 K
We need to calculate the value of
We know that,
Hence, The value of is
.