Answer:
v = 5.42 m/s
Explanation:
given,
height of the jumper = 1.5 m
velocity of sprinter = ?
kinetic energy can be transformed into potential energy
v = 5.42 m/s
Speed of the sprinter is equal to v = 5.42 m/s
A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte
rn on a screen 60.0 cm from the slits, and measures the distance between the first and tenth maxima to one side of the central bright spot to be 17.0 mm. What is the wavelength of the light that was used in the experiment?
1 answer:
You might be interested in
(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
Answer:
option C
Explanation:
given,
mass of the three planet is same
radius of the planets are
R₁ > R₂ > R₃
expression of escape velocity
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
from the above expression we can clearly conclude that the escape velocity is inversely proportional to the radius of the Planet.
radius of planet increases escape velocity decreases.
Hence planet 3 has the smallest radius so the escape velocity of the third planet will be maximum.
The correct answer is option C
Answer:
Detailed solution is given below
