A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte
rn on a screen 60.0 cm from the slits, and measures the distance between the first and tenth maxima to one side of the central bright spot to be 17.0 mm. What is the wavelength of the light that was used in the experiment?
1 answer:
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The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
- The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
Which gives;
F₀ = T₂·sin(37°)
Which gives;
- F₀ ≈ <u>0.377·M·g</u>
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