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Nesterboy [21]
3 years ago
10

A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte

rn on a screen 60.0 cm from the slits, and measures the distance between the first and tenth maxima to one side of the central bright spot to be 17.0 mm. What is the wavelength of the light that was used in the experiment?

Physics
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

Wavelenght is 4.53x10^-7m

Explanation:

Detailed explanation and calculation is shown in the image below

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What system will break the chewed food down to a form your cell can use
horsena [70]
If I'm not mistaken it should be the digestive system due to the fact that our mouths and stomachs break down food and our intestines absorb any water and nutrients
4 0
4 years ago
While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke
3241004551 [841]

Answer:

The right shoe

Explanation:

Both shoes have the same speed.

5 0
4 years ago
The second minimum in the diffraction pattern of a 0.11-mm-wide slit occurs at 0.72°. What is the wavelength of the light?
Anit [1.1K]

Answer:

691.13 nm

Explanation:

d = width of the slit = 0.11 x 10⁻³ m

θ = angle of diffraction pattern = 0.72° degree

λ = wavelength of the light = ?

m = order = 2                              (since second minimum)

for the second minimum diffraction pattern we use the equation

d Sinθ = m λ

Inserting the values

(0.11 x 10⁻³) Sin0.72 = (2) λ

λ = 691.13 x 10⁻⁹ m

λ = 691.13 nm

6 0
3 years ago
What is the definition of Cubit
disa [49]

Answer:

See below.

Explanation:

Cubit is a unit of length based on the length of the forearm from the elbow to the tip of the middle finger and usually equal to about 18 inches (46 centimeters).

It is an ancient unit of length used in ancient Egypt and is also known as "ancient Egyptian royal cubit."

Other similar units of measurements are displayed in the image below. Thanks!

7 0
3 years ago
A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
8_murik_8 [283]

Answer:

t = 0.28 seconds

Explanation:

Given that,

Force acting on a firework, F = 700 N

The momentum of the firework, p =200 kg-m/s

We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,

F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s

So, the required time is equal to 0.28 seconds.

7 0
3 years ago
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