Answer:
Zinc- Zn
Mass Numbers:
Tin-118.71 u
Zinc- 65.38
Protons:
Tin-50
Atomic number zinc 45.38
Zinc has 30 electrons
Tin has 50 electrons
35 neutrons in zinc
iodine-
atomic number- 53
78 neutrons
cl-1 is chlorine
atomic number 17
18 neutrons
17 electrons
atomic number 35 is bromine
symbol Br
35 protons
45 neutrons
35 electrons
Aluminium
protons and electrons 13
neutrons 14
atomic number 14
fe+2
26 protons
24 electrons
30 neutrons
ferrous iron
Cu+1 copper
63.546 mass number
proton and electron 29
neutron 35
Answer:
Force = 100N
Explanation:
Force = mass × acceleration
Answer:
The angle is 65.6°.
Explanation:
Given that,
Speed = 2.20 m/s
Distance from the shore= 500 m
Distance from the bottom= 1100 m
Speed of boat = 7.30 m/s
According to figure,
We need to calculate the angle with shore
Using formula of angle
Put the value into the formula
We need to calculate the angle
Put the value into the formula
Hence, The angle is 65.6°.
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7. First write down all the known variables while separating the values for each direction:
x-direction:
vix = 20m/s
vfx = 20m/s
x = 39.2m
y-direction:
viy = 0m/s
ay = -9.8m/s^2
y = ?
Based on the knowns, the first step is to calculate the time of flight from the x-direction as it will be the same as value for the y-direction. Find the correct kinematic equation to do so:
x = (1/2)(vix+vfx)t
(39.2) = (1/2)(20+20)t
1.96s = t
Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the y-direction:
y = viy*t + (1/2)ay*t^2
y = (0)(1.96) + (1/2)(-9.8)(1.96)^2
y = -18.82m (Value is negative because gravity constant was negative. It is the height reference that from the top of the building down, which is why it is negative. The sign can be ignored for this question.)
8. First write down all the known variables while separating the values for each direction:
x-direction:
x = 12m
vfx = 0m/s
vix = ?
y-direction:
y1 = 1.2m
y2 = 0.6m
viy = 0m/s;
ay = -9.8m/s^2
First find time in the y-direction as it would be the same value for the x-direction.
(y2 - y1) = viy*t + (1/2)ay*t^2
(-0.6) = (0)t + (1/2)(-9.8)t^2
t = 0.35s
Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the x-direction:
x = (1/2)(vix+vfx)t
(12) = (1/2)(vix+(0))(0.35)
68.6m/s = vix
