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dolphi86 [110]
4 years ago
12

Which phenomenon occurs when a wave encounters a non–transmitting barrier

Physics
2 answers:
SpyIntel [72]4 years ago
6 0

Answer:

Absorption

Explanation:

A non-transmitting barrier would not allow a wave to go through. When a wave is unable to pass through a barrier, it is not transmitted and can get absorbed or reflected back. The wave can also try to go round the barrier.

Most likely, the wave gets absorbed by the barrier and it stops it.

kozerog [31]4 years ago
3 0

Answer:

C.  reflection of the wave with the same wave speed

Explanation:

A.  refraction of the wave with a different wave speed

B.  reflection of the wave with a different wavelength

C.  reflection of the wave with the same wave speed

D.  refraction of the wave with a different wavelength

Plato said C was right

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Find the missing spaces in the charts below! Please!
Neko [114]

Answer:

Zinc- Zn

Mass Numbers:

Tin-118.71 u

Zinc- 65.38

Protons:

Tin-50

Atomic number zinc 45.38

Zinc has 30 electrons

Tin has 50 electrons

35 neutrons in zinc

iodine-

atomic number- 53

78 neutrons

cl-1 is chlorine

atomic number 17

18 neutrons

17 electrons

atomic number 35 is bromine

symbol Br

35 protons

45 neutrons

35 electrons

Aluminium

protons and electrons 13

neutrons 14

atomic number 14

fe+2

26 protons

24 electrons

30 neutrons

ferrous iron

Cu+1  copper

63.546 mass number

proton and electron 29

neutron 35

5 0
3 years ago
What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?
Llana [10]

Answer:

Force = 100N

Explanation:

Force = mass  × acceleration

3 0
3 years ago
A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 2.20 m/s
zmey [24]

Answer:

The angle is 65.6°.

Explanation:

Given that,

Speed = 2.20 m/s

Distance from the shore= 500 m

Distance from the bottom= 1100 m

Speed of boat = 7.30 m/s

According to figure,

We need to calculate the angle with shore

Using formula of angle

\tan\theta=\dfrac{y}{x}

Put the value into the formula

\tan\theta=\dfrac{500}{1100}

\theta=\tan^{-1}(\dfrac{500}{1100})

\theta=24.4^{\circ}

We need to calculate the angle

\alpha=90-\theta

Put the value into the formula

\alpha=90-24.4

\alpha=65.6^{\circ}

Hence, The angle is 65.6°.

5 0
3 years ago
Which of the following statements about horizons is true?. a. They are characterized by whether they are solid, liquid, or gas..
garik1379 [7]
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3 0
4 years ago
Someone answer these questions PLEASEE
lara31 [8.8K]

7.  First write down all the known variables while separating the values for each direction:

x-direction:

vix = 20m/s

vfx = 20m/s

x = 39.2m

y-direction:

viy = 0m/s

ay = -9.8m/s^2

y = ?

Based on the knowns, the first step is to calculate the time of flight from the x-direction as it will be the same as value for the y-direction.  Find the correct kinematic equation to do so:

x = (1/2)(vix+vfx)t

(39.2) = (1/2)(20+20)t

1.96s = t

Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the y-direction:

y = viy*t + (1/2)ay*t^2

y = (0)(1.96) + (1/2)(-9.8)(1.96)^2

y = -18.82m  (Value is negative because gravity constant was negative.  It is the height reference that from the top of the building down, which is why it is negative.  The sign can be ignored for this question.)


8.  First write down all the known variables while separating the values for each direction:

x-direction:

x = 12m

vfx = 0m/s

vix = ?

y-direction:

y1 = 1.2m

y2 = 0.6m

viy = 0m/s;

ay = -9.8m/s^2

First find time in the y-direction as it would be the same value for the x-direction.

(y2 - y1) = viy*t + (1/2)ay*t^2

(-0.6) = (0)t + (1/2)(-9.8)t^2

t = 0.35s

Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the x-direction:

x = (1/2)(vix+vfx)t

(12) = (1/2)(vix+(0))(0.35)

68.6m/s = vix

6 0
4 years ago
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