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Kisachek [45]
3 years ago
7

Based on the results of your investigation,make a claim about how changing the size or shape of an object affects its density?

Chemistry
2 answers:
Nitella [24]3 years ago
6 0
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Elodia [21]3 years ago
5 0

Answer:

It can affect it by taking away mass and volume. Mass and Volume are the two factors that calculate and make up density

Explanation:

Mass/Volume =Density

If you were to change the mass or volume by changing the size or shape of an object, then this would affect the density.

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The ph of a 0.30 m solution of a weak acid is 2.67. what is the ka for this acid?
azamat
To determine the Ka of the acid, we can use the equation for the pH of weak acids which is expressed as:

pH = -0.5 log Ka
2.67 = -0.5 log Ka
Ka = 4.571x10^-6

Weak acids are acids that do not dissociate completely in solution. The solution would contain the cations, anions and the acid itself as a compound. Hope this helps.
7 0
3 years ago
Read 2 more answers
Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
2 years ago
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem
Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

R=0.08205L.atm/mol.K

R=8.3145L.kPa/mol.K

R=8.3145J/mol.K 

R=1.987cal/mol.K

R=0.08314L.bar/mol.K

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

3 0
3 years ago
For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are
34kurt

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

<h3>ΔG = -6.5kJ/mol at 500K</h3>

8 0
2 years ago
Part 1 of 1 - Question 3 of 20 5.0 Points 2H2 O2 - &gt; 2H2O can be classified as what type of reaction?
mart [117]
2 H₂ + O₂ = 2 H₂O


Answer B    only synthesis.

hope this helps!
7 0
3 years ago
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