Answer:
![\boxed{\text{10 \%}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B10%20%5C%25%7D%7D)
Explanation:
The formula for efficiency is
![\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Ctext%7BEfficiency%7D%20%26%20%3D%20%26%20%5Cdfrac%7B%5Ctext%7Buseful%20energy%20out%7D%7D%7B%5Ctext%7Benergy%20in%7D%7D%20%5Ctimes%20100%20%5C%2C%5C%25%20%5C%5C%5C%5C%5Ceta%20%26%20%3D%20%26%20%5Cdfrac%7Bw_%7B%5Ctext%7Bout%7D%7D%7D%7Bw_%7B%5Ctext%7Bin%7D%7D%20%7D%20%5Ctimes%20100%20%5C%2C%5C%25%5C%5C%5Cend%7Barray%7D)
Data:
Useful energy = 3 J
Energy input = 30 J
Calculation:
![\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Ceta%20%26%20%3D%20%26%20%5Cdfrac%7B%5Ctext%7B3%20J%7D%7D%7B%5Ctext%7B30%20J%7D%7D%20%5Ctimes%20100%20%5C%2C%5C%25%5C%5C%5C%5C%5Ceta%20%26%20%3D%20%26%2010%20%5C%2C%20%5C%25%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7B%20The%20efficiency%20is%20%7D%5Cboxed%7B%5Ctextbf%7B10%20%5C%25%7D%7D)
SUBTRACTION.
explanation: PEMDAS, The last one is subtraction
Answer:
store water, waste, and nutrients for the cell
Answer:
7.68%
Explanation:
Let's consider the neutralization reaction between acetic acid and sodium hydroxide.
HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O
25.56 mL of 0.200 M NaOH reacted. The reacting moles of NaOH are:
0.02556 L × 0.200 mol/L = 5.11 × 10⁻³ mol
The molar ratio of HC₂H₃O₂ to NaOH is 1:1. The reacting moles of HC₂H₃O₂ are 5.11 × 10⁻³ moles.
The molar mass of acetic acid is 60.05 g/mol. The mass corresponding to 5.11 × 10⁻³ moles is:
5.11 × 10⁻³ mol × 60.05 g/mol = 0.307 g
0.307 g of acetic acid are in 4.00 g of vinegar. The mass percent of HC₂H₃O₂ is:
0.307 g/4.00 g × 100% = 7.68%
<h3><u>Answer;</u></h3>
= 459 g of Aspartame
<h3><u>Explanation;</u></h3>
1 mole of aspartame = 294.3 g
But;
Moles = mass/molar mass
Therefore;
Mass = moles × molar mass
= 1.56 moles × 294.3 g/mol
= 459 g of Aspartame