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3 years ago

Classify each of the following chemical reaction (check all that apply) :

Chemistry

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

(1 ) acid-base, double replacement

(2) double replacement

(3) combustion, combination

(4) double replacement, precipitation

Explanation:

(1) Recognize this as the reaction of the acid (HI) with the base (NaOH) to produce salt (NaCl) and water.

This reaction is also a double replacement since Na replaces H in HI,and H replaces Na in NaOH.

(2) Here we have a double replacement where Cu replaces Zn in ZnCrO4, and Zn replaces Cu in CuSO4

(3) Here we have the combustion of the organic compound CH3CH2OH (ethanol) with oxygen to produce CO2 and water.

This reaction is also a combination reaction reaction of oxygen with CH3CH2OH

(4) This reaction is also a double replacement where Ag replaces Na in NaCl and Na replaces Ag in AgNO3

The reaction is also a precipitation reaction where a precipitate AgCl is formed from the reaction of aqueous NaCl plus AgNO3 to produce solid AgCl and aqueous NaNO3.

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3. Fill in: Name the organelle or organelles that perform each of the following functions.

Mekhanik [1.2K]

A. Chloroplasts

B. The cell wall and the vacuole

C. Vacuoles

D. The mitochondrion

8 0

3 years ago

Calculate the equilibrium constant for the reaction using the balanced chemical equation and the concentrations of the substance

Oliga [24]

Answer:

4.75 is the equilibrium constant for the reaction.

Explanation:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Equilibrium concentration of reactants :

$[CO]=0.0590 M,[H_2O]=0.00600 M$

Equilibrium concentration of products:

$[CO_2]=0.0410 M,[H_2]=0.0410 M$

The expression of an equilibrium constant is given by :

$K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}$

$K_c=\frac{0.0410 M\times 0.0410 M}{0.0590M\times 0.00600 M}$

$K_c=4.75$

4.75 is the equilibrium constant for the reaction.

3 0

3 years ago

What is the molarity (M) of the following solutions?

Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

= 27 + 3(16 + 1)

= 27 + 3(17) = 27 + 51

= 78 g/mole

$Al(OH)_3$ = 78 g/mole

Given mass= 19.2 g/mole

$Mole = \frac{Given\ mass}{Molar\ mass}$

$Mole = \frac{19.2}{78}$

Moles = 0.246

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

Volume = 280 mL = 0.280 L

$Molarity = \frac{0.246}{0.280)}$

Molarity = 0.879 M

Molarity = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

$Mole = \frac{235.9}{119}$

Moles = 1.98

Volume = 2.6 L

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

$Molarity = \frac{1.98}{2.6)}$

Molarity = 0.762 M

Molarity = 0.76 M

4 0

3 years ago

List the protons, neutrons, and electrons for Ge2+<br> Please hurry

Nady [450]

Answer:

32, 30 and 41

Explanation:

The problem here is to find the number of:

Protons, neutrons and electrons in Ge²⁺

In this ion,

We must understand that for a net positive charge to remain on an atom, the number of protons must be greater than the number of electrons.

Ge is Germanium with atomic number of 32;

So the number of protons is 32

Since the atom has lost two electrons;

Number of electrons now is 32 - 2 = 30

Number of neutrons is 41 from the periodic table.

7 0

3 years ago

What molecule is needed to digest milk?

xxMikexx [17]

Answer:

For example, the sugar found in milk is called lactose. With the aid of the enzyme, lactase, the substrate, lactose, is broken down into two products, glucose and galactose. People who don't make enough lactase have trouble digesting milk products and are lactose intolerant.

4 0

3 years ago