Answer:
The Answer Is Chemical Change :)
Answer:
-3.617 °C
Explanation:
Step 1: Given data
Mass of water (m): 210.0 g
Energy released in the form of heat (Q): -3178 J (the minus sign corresponds to energy being released)
Specific heat of water (c): 4.184 J/g.°C
Temperature change (ΔT): ?
Step 2: Calculate the temperature change
We will use the following expression.
Q = c × m × ΔT
-3178 J = 4.184 J/g.°C × 210.0 g × ΔT
ΔT = -3.617 °C
Explanation:
hope this helps you..........
called the Avogadro number
N(A)= 6.02 x 10^23 mol^-1
1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules.
thus, 1.14moles will contain;
= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 2.05884 x 10^24 oxygen atoms
= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 6.8628 x 10^23 sulfur atoms
hope this helps:-)
The purpose is to make glucose.
