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Allushta [10]
3 years ago
11

What do you need to know to be able to determine how far a projectile travels horizontally?

Physics
1 answer:
Effectus [21]3 years ago
5 0
As for me, there are two suitable answers for the question represented above and here is a short explanation why I consider these two to be correct : 
D. The horizontal velocity of the projectile and <span>B. The length of time before it lands 
</span>v_x = v*cos(x) [&#10;&#10;d_x = v_x(t) + ½at² -- this led me to answers! Hope everything is clear! Regards!<span>
</span>
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In which of these scenarios would the sound of a drumstick hitting a metal bar get to you in the least amount of time?explain ur
MA_775_DIABLO [31]

Answer:

Scenario 1 is the correct answer.

Explanation:

The sound of the drumstick hitting the metal bar will get to me in a shorter amount of time in Scenario 1 . The sound wave will travel faster in the metal bar than through the air because the speed of sound waves in solid is faster than it is in gases.

6 0
3 years ago
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PLEASE HELP ME
Snowcat [4.5K]

Answer:

Compound.

Explanation:

6 0
4 years ago
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4. What are three tips parents can use to improve communication with their children? Discuss one that you think is most importan
Mumz [18]
Have them give up there phone for 15 minutes
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4 0
3 years ago
Zad. 2 W marszobiegu chłopiec przebiegł 900 m w ciągu 205 min, a następnie przeszedł 300m w tym danym czasie. Jaka była średnia
USPshnik [31]

Odpowiedź:

0,049 m / s

Wyjaśnienie:

Biorąc pod uwagę, że:

Dystans biegu = 900m

Czas trwania = 205 minut

Długość przejścia = 300 m

Zajęty czas = 205 minut

Średnia prędkość :

(Przebieg + pokonany dystans) / całkowity czas

Średnia prędkość :

(900 m +. 300 m) / 205 + 205

1200 m / 410 minut

Minuty do sekund

1200 / (410 * 60)

1200/24600

= 0,0487804

= 0,049 m / s

8 0
3 years ago
1. A pendulum has a period of 3 seconds. What's its frequency? 2. A pendulum has a frequency of 0.25 Hz. What's its period? 3. A
RideAnS [48]

Answer:

(1) 0.333 Hz

(2) 4 sec

(3) 2 sec, 0.5 Hz

Explanation:

(1) We have given time period of pendulum is 3 sec

So T = 3 sec

Frequency will be equal to f=\frac{1}{T}=\frac{1}{3}=0.333Hz

(2) Frequency of the pendulum is given f = 0.25 Hz

Time period is equal to T=\frac{1}{f}=\frac{1}{0.25}=4sec

(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds

So time taken to complete 1 back and forth swings = =\frac{20}{10}=2sec

So time period T = 2 sec

Frequency will be equal to f=\frac{1}{T}=\frac{1}{2}=0.5Hz

6 0
3 years ago
Read 2 more answers
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