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xeze [42]
2 years ago
5

Given that a mass of a ball is (36.0 g), and the volume is (8.0 mL), what is the ball's density in g/mL?​

Chemistry
1 answer:
max2010maxim [7]2 years ago
5 0

Answer:

4.5g/mL

Explanation:

Given parameters:

Mass of ball  = 36g

Volume of the ball  = 8mL

Unknown:

Density of the ball  = ?

Solution:

Density is the mass per unit volume of a substance.

          Density  = \frac{mass}{volume}  

So;

 Density  = \frac{36}{8}    = 4.5g/mL

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What is a magnetic field
babymother [125]

a region around a magnetic material or a moving electric charge within which the force of magnetism acts.

5 0
3 years ago
Is a solution in which (OH) = 1.0 10-1M acidic, basic, or neutral?
astra-53 [7]

Answer:

The pH is 13,00 and the solution is basic.

Explanation:

<em> </em>The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and higher than 7 to 14 basic. It is calculated as

pH = -log (H 30+)

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

[H3O ^ +]x [OH ^ -] = 1x 10 ^ -14

[H3O ^ +]x [1.0 10-1]=1x 10 ^ -14

[H3O ^ +]= 1x 10 ^ -14/1.0 10-1M= <em>1.0 10-13 M</em>

pH = -log (H 30+)= -log (1.0 10-13 M)= <em>13, 00</em>

As the pH value is higher than 7, it corresponds to a basic substance.

5 0
3 years ago
An object is hit with a force of 5 Newtons and accelerates to 36 m/s2. What is the mass of the object
mrs_skeptik [129]

Answer:

Mass = 0.139 kg

Explanation:

There is a formula in terms of force, acceleration and mass which is:

Force = mass × acceleration

Put the values into the formula.

5 = m × 36

m = 5 ÷ 36

<u>m = 0.139 kg</u>

6 0
2 years ago
1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate
Whitepunk [10]

a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g

6 0
2 years ago
A hydrocarbon with vapour density
Dafna1 [17]

Answer:

the answer is C4H10 I hope I helped

4 0
2 years ago
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