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3 years ago

When magnesium loses it's valence electrons, it has the atomic structure of what element?

1 answer:

4 0

As far as I can tell the best answer for this would be (A) Neon. However, I would argue that this is at the very least a misleading question. Atoms are less identified by their electrons than their protons (which is represented always by its atomic number). Although atoms can gain or lose electrons, the protons would never change (and remain the same element). Personally, I would have written the question as, "When Magnesium loses its valence electrons, its new number of electrons would most closely resemble _____"

You might be interested in

Which major changes in human society and the environment occurred during the Industrial Revolution? *

wariber [46]

Answer: c

Explanation:

during the industrial revolution americans were switching from rural to urban life, thus using up more fossil fuels, and working in factories

7 0

3 years ago

The pressure of a gas sample at 60.0 °C is decreased from 3.40 atm to 2.60 atm by cooling at a constant volume. What is the temp

mrs_skeptik [129]

151.29 degrees Celsius

4 0

2 years ago

A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio

____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

The units are mole fraction, molality and mass%

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = 59,0 moles of water

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = 0,0157

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = 0,889m

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = 16%

I hope it helps!

6 0

3 years ago

Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 1.90 105 m/s

alina1380 [7]

To determine the temperature of the gas, we need an expression which would relate the average speed of the molecules of the gas and the temperature. From my readings, it is said that the average kinetic energy ( energy of an object in motion) of the molecules of a gas is directly related to the temperature of the gas system. Since velocity or speed is directly related to kinetic energy, it should be that temperature is directly related to the average speed. The expression would be:

v^2 = 3RT/M
(1.90x10^5)^2 = [3(8.314)T] / [44.0(1/1000)]
T = 63683746.3 K

The temperature would be 63683746.3 K.

5 0

4 years ago

Radical's of

aivan3 [116]

Answer:

1..CO3

2..OH

3..CO

4..Cl

5..PO3

6..SO4

8..NO3

9..NO2

1O..I2

8 0

3 years ago