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Dmitriy789 [7]
3 years ago
10

When magnesium loses it's valence electrons, it has the atomic structure of what element?

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0

As far as I can tell the best answer for this would be (A) Neon. However, I would argue that this is at the very least a misleading question. Atoms are less identified by their electrons than their protons (which is represented always by its atomic number).  Although atoms can gain or lose electrons, the protons would never change (and remain the same element). Personally, I would have written the question as, "When Magnesium loses its valence electrons, its new number of electrons would most closely resemble _____"

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Using isotope, can we trace back again our ancestors? How?​
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4 0
3 years ago
Determine the rate of a reaction that follows the rate law rate = k a m b i where
ikadub [295]
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
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6 0
3 years ago
Why would a scientist only use observations to formulate a theory rather than follow the scientific method?
Alenkinab [10]

Answer: Observation is essential in science. Scientists use observation to collect and record data, which enables them to construct and then test theories

Explanation:

7 0
2 years ago
3. Which of the following are missing from the food web shown below?
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5 0
3 years ago
a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is
Leona [35]

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is 2.7 g/cm^{3}. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

V=\frac{m}{d}

Putting the values.

V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}

The volume of cuboid is l\times b\times h, the length and breadth are given, height can be calculated as follows;

h=\frac{V}{l\times b}

Putting the values,

h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is 9.7\times 10^{-3}cm

7 0
3 years ago
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