Complete Question
The speed of a transverse wave on a string of length L and mass m under T is given by the formula

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Answer:

Explanation:
From the question we are told that
Speed of a transverse wave given by

Maximum Tension is 
Generally making
subject from the equation mathematically we have




Therefore the Linear mass in terms of Velocity is given by

A wave is a disturbance that moves along a medium from one end to the other. If one watches an ocean wave moving along the medium (the ocean water), one can observe that the crest of the wave is moving from one location to another over a given interval of time. The crest is observed to cover distance. The speed of an object refers to how fast an object is moving and is usually expressed as the distance traveled per time of travel. In the case of a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given interval of time. In equation form,
A pure substance that is made up of only one kind of atom is called an element
From A to B its 5 ohm.
above shown 6 and 12 ohm resistors are in parallel to short circuit hence their equivalent resistance is zero.
(Current doesnt flow through a resisstor if there is a Short circuit alternate.
Answer:
(a) Initial volume will be 7.62 L
(b) Final temperature will be 303.85 K
Explanation:
We have given one mole of ideal gas done 3000 J
So work done W = 3000 J
Let initial volume is
and initial pressure
( As pressure is constant )
Final volume
= 0.025 
Number of moles n = 1
(B) From ideal gas of equation we know that 
So 
T = 303.85 Kelvin
(B) For isothermal process work done is equal to





So initial volume will be 7.62 L