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mixer [17]
3 years ago
10

While two forces act on it, a particle of mass m=3.2kg is it to move continuously with velocity (3m/s)i - (4m/s)j . one of the f

orces is F1 = (2N)i + (-6N)j . what is the other force?
Physics
1 answer:
marta [7]3 years ago
8 0
Mmm tricky.
Since the velocity is constant, I'm going to assume there is no acceleration in any direction. This means there is no net force in the I or J forection!

Since there are 2 forces, both must be equal and opposite in direction to perfectly cancel each other out.

So the opposite of F1 is (-2N)I + (6N)J!

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if the user exerts a 14 n force on the upper handle, estimate the force on the clove. express your answer with the appropriate u
Marizza181 [45]

The force on the clove will have the same magnitude but a negative sign with it that is F = - 14 N

<h3>What is force and how do we calculate it ?</h3>

The definition of force is: The pushing or pulling on a massed object changes its velocity. Force is an external agent that has the power to alter a body's resting or moving condition.

It has a size and a movement.

Newton's second law of motion defines the force formula as follows:

A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force.

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3 0
1 year ago
If an object is being pulled by two forces, one 4 N to the left and the other 2 N to the right, what is the net
nika2105 [10]

Answer:

2N

Explanation:

subtract  rthe two forces to see which is greater

4-2=2

6 0
3 years ago
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Vinvika [58]

Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

5 0
3 years ago
The unit of power of a lens is.<br>(a) Metre<br>(b) Dyne<br>(c) Dioptre​
zhenek [66]

Answer:

c. dioptre that's the answer.

5 0
3 years ago
Read 2 more answers
A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​
Illusion [34]

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

W=mg\Delta h

where

m is the mass of the object

g is the acceleration of gravity

\Delta h is the change in height of the object

For the object in this problem, we have:

m = 5 kg

g=10 m/s^2

\Delta h = 2 m

Substituting into the equation,

W=(5)(10)(2)=100 J

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3 0
3 years ago
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