You will have 34 hydrogen atoms
<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid = 
The chemical equation for the combustion of oleic acid follows:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(18\times \Delta H^o_f_{(CO_2(g))})+(17\times \Delta H^o_f_{(H_2O)})]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%2818%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%2B%2817%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![-1.11\times 10^4=[(18\times (-393.51))+(17\times (-241.82))]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times 0)]\\\\\Delta H^o_f_{(C_{18}H_{34}O_2(l))}=-94.12kJ/mol](https://tex.z-dn.net/?f=-1.11%5Ctimes%2010%5E4%3D%5B%2818%5Ctimes%20%28-393.51%29%29%2B%2817%5Ctimes%20%28-241.82%29%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%200%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%3D-94.12kJ%2Fmol)
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
Answer:
B. gas>liquid>solid
Explanation:
Entropy increases with increase in randomness,in gas randomness is higher than in liquid than in solid!
✌️:)
The formula for density is:

We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.
The volume is unknown, so we can simply denote it as "x"

multiply both sides by x

The x's cancel out on the right side and you are left with

From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.


Round to 3 significant figures, and your final answer is:

The volume of the sample of mercury was 3.96 mL.
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as

For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions

(b) For 200°C and 1.1 atm,

Then the concentration in mg/m3 is
