7.6 is the answer for the question
Answer:
Mass ratio of magnesium = 2 : 1
Explanation:
Let us write down the masses of element involve to form the compounds .
Compound A → 7.88 g of mg and 15.68 g of 02
Compound B → 2.12 g of mg and 6.91 g of 02
since we want to get the mass ratio of magnesium, we divide the mass of mg with the other element present (oxygen) . we want to make both compound in equal proportions.
Compound A → 7.88 / 15.68 = 0.5025510204 g of Mg
/1 g of Oxygen
Compound B → 2.12 / 6.91 = 0.30680173661 g of Mg/ 1 g of Oxygen
Mass ratio of magnesium = compound A(Mg)/compound B(Mg)
Mass ratio of magnesium = 0.5025510204/0.30680173661
Mass ratio of magnesium = 1.63803186368
/1
Mass ratio of magnesium = 2 : 1
- 1-ethyl-3-propylcyclopentane
- 1,2-dimethylcyclopentene
- 1,3,5-Triethylbenzene
<h3>What is IUPAC rule?</h3>
The IUPAC nomenclature system is a set of logical rules devised and used by organic chemists to circumvent problems caused by arbitrary nomenclature.
The 1-ethyl-3-propylcyclopentane molecule contains a total of 30 bond(s) There are 10 non-H bond(s), 3 rotatable bond(s) and 1 five-membered ring(s).
The 1,2-dimethylcyclopentene molecule contains two methyl groups and one double bond in the ring.
The 1,3,5-Triethylbenzene molecule contains three ethyl groups and a benzene ring.
Learn more about the IUPAC rule here:
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Convert grams to moles
moles to moles
moles to grams
A. 2.99g
b. 20.88g
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