Alvin is heating a solution in his chemistry lab. The temperature of the solution is at 14°C. He turns on the burner and finds t
hat the solutions temperature increases 2°C every minute. This graph shows the temperature change.
1 answer:
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<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid =
The chemical equation for the combustion of oleic acid follows:
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as
The equation used to calculate enthalpy change is of a reaction is:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
The formula for density is:
We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.
The volume is unknown, so we can simply denote it as "x"
multiply both sides by x
The x's cancel out on the right side and you are left with
From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.
Round to 3 significant figures, and your final answer is:
The volume of the sample of mercury was 3.96 mL.
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is