This is an insidious question. Quite frankly, I would not have expected to see it here on Brainly. But I'm ready to play the cards that you have dealt me.
None of the choices offered is a correct solution.
If the output of the AC generator is nice and sinusoidal, and its maximum (peak) emf is 150 volts, then its RMS emf is
(1/2) (150) (√2) = 106.07 volts.
The resistor's dissipation is
Power = (current) x (voltage) .
If the resistor is dissipating its full rated 35W, then
The largest choice ... 3.1 A ... is the current in a resistor that is dissipating 35W if the voltage is
(35W / 3.1A) = 11.29 volts .
The smallest choice ... 1.2 A ... is the current in a resistor that is dissipating 35W if the voltage is
(35W / 1.2A) = 29.17 volts .
Whatever you meant the so-called "150 V" of the generator to represent ... whether the RMS sinusoidal, peak sinusoidal, peak square-wave, RMS square-wave, DC,average, etc. ... none of the choices for current, in combination with any of these generators, would dissipate 35W.
The primary reason for this is efficiency. In most applications, a lower resistance means less power is converted to heat and lost to the surrounding environment and more of the supplied power gets to its intended destination.
