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dsp73
3 years ago
15

What is a good example of netwon 3rd law​

Physics
1 answer:
satela [25.4K]3 years ago
8 0

A fish pushes water backwards in order to move forward is a good example of Newton's 3rd Law.

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50 Point Physics Question!
harina [27]

Answer:

dfsdfgsdfaefffsfffefefef

Explanation:

eg3g3gf3f3f3f3f3f3f3f3f3f3ggeg

7 0
3 years ago
A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/
Anastasy [175]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

KE_i + PE_i = KE_f + PE_f

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0

\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2

So by solving above equation we will have

v_f = 84.3 m/s

now in order to find the momentum we can use

P = mv

P = 1.25 \times 84.3

P = 105.4 kg m/s

3 0
3 years ago
The term "ideal gas" refers to a gas for which certain assumptions have been made. Which of the following is not such an assumpt
Jobisdone [24]

Answer:

(A) Consists of a small number of tiny particles that are far apart- relative in their size.

Explanation:

An <em>ideal gas</em> is defined as a simplification of a real gas, with punctual particles, in which all collisions are elastic, with random displacements and with no attractive force between them.

The assumption of the particles being punctual make clear that they do not have size at all. So if they were far apart-relative in their size, they can not collide each other, that is why assumption (B) can not be possible (<u><em>for that particular case</em></u>).

It is clear that (A) is not an assumption for an ideal gas, because do not fit in any of its properties.

Elastic collision: It is a case in which the energy is conserved (Kinetic Energy).

Kinetic Energy: It is the energy that will have an object as a consequence of its movement.

6 0
3 years ago
A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high te
Nataly [62]

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

\Delta L=\alpha L_{0}\Delta T

Where:

  • L(0) is the initial length
  • ΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))
  • ΔL is the final length minus the initial length (L(f)-L(0))
  • α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)  

So, we have:

L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})

L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})

L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)

L_{f}=0.117\: m

Therefore, the length at the final temperature is 11.7 cm.

I hope it helps you!

7 0
3 years ago
In an experiment, James studied the relationship between kinetic energy, mass, and velocity. Four masses were rolled across a sm
Alex777 [14]

Answer:

20

Explanation:

3 0
3 years ago
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