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dsp73
3 years ago
15

What is a good example of netwon 3rd law​

Physics
1 answer:
satela [25.4K]3 years ago
8 0

A fish pushes water backwards in order to move forward is a good example of Newton's 3rd Law.

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An organ system is best described by which of the following?
earnstyle [38]
A group of cells together
3 0
3 years ago
Read 2 more answers
the electric current in a wire is 1.5 A. How many electrons flow past a given point in a time of 2 s?​
34kurt

Answer:

The quantity of electrons that flows past a given point is 3.0 C.

Explanation:

An electric current (I) is the ratio of the quantity of charges (Q) that flows through a point to the time taken (t).

i.e            I = \frac{Q}{t}

It is measured in Ampere's by the use of an ammeter in the laboratory. The quantity of charge that flow through a given point is measured in Coulombs, while time is measured in seconds.

Given that;     I = 1.5A and t = 2s, find Q.

                          Q = It

                             = 1.5 × 2

                             = 3.0 C

The quantity of electrons that flows past a given point is 3.0 C.

6 0
3 years ago
If you increase the voltage what will the current do
o-na [289]

Answer:

The power will remain the same for a particular load as we are not changing the load. so if we increase the voltage, the current will decrease to make the net power consumed by the load same as before. If we increase the current, the voltage will decrease for making the power same. The power will only change when we changes the load.

Explanation:

8 0
2 years ago
The part of the electromagnetic spectrum you can see is called ultraviolet light. Please select the best answer from the choices
Artyom0805 [142]
True because when the light bounces off a surface it creates a rainbow which we call roygbiv
4 0
3 years ago
A race car starts from rest on a circular track of radius 378 m. The car's speed increases at the constant rate of 0.580 m/s2. A
insens350 [35]

Answer:

a) V=14.904m/s

b) d = 191.49 m

c) t= 25.696 s

Explanation:

From the question we are told that:

Radius r =378m

Acceleration a=0.580

a)

Generally the  equation for speed of the car is mathematically given by

 a=\frac{v^2}{r}

 V=\sqrt{a*r}

 V=\sqrt{0.58*383}

 V=14.904m/s

b)

Generally the  equation for distance traveled of the car is mathematically given by

 V^2=u^2+2ad

 d=\frac{V^2}{2a}

 d=\frac{14.904^2}{2*0.58}  

 d = 191.49 m

c)

Generally the  equation for time of the car is mathematically given by

 V=u+at

 t=\frac{V}{a}

 t=\frac{14.904}{0.58}

 t= 25.696 s

3 0
3 years ago
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