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I am Lyosha [343]
3 years ago
10

Newton's cradle consists of an aligned row of identical elastic balls suspended by strings so they barely touch one another. whe

n two balls are raised from one end and released, they strike the row and two balls pop out from the other end. if instead, one ball popped out with twice the speed of the two, this would violate
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Initial momentum = 2 * m v

so if 1 ball popped out with 2 v momentum would be conserved

but the initial kinetic energy of the two balls is

1/2 m v^2 + 1/2 m v^2 = m v^2

But the kinetic energy of one ball with twice the speed would be

KE = 1/2 m (2 v)^2 = 2 m v^2 thus violating conservation of energy

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Answer:

A. 8.29\times 10^{-18}\ J

Explanation:

Given that:

p = magnitude of charge on a proton = 1.6\times 10^{-19}\ C

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r = distance between the two carbon nuclei = 1.00 nm = 1.00\times 10^{-9}\ m

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

U = \dfrac{kQq}{r}

So, the potential energy between the two nuclei of carbon is as below:

U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J

Hence, the energy stored between two nuclei of carbon is 8.29\times 10^{-18}\ J.

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3 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. Estimate the kinetic energy acquired by
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Answer:

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3 years ago
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