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3 years ago

9

Find mZLNM. M L 1089 P N

1 answer:

marysya [2.9K]3 years ago

3 0

Answer: 108*3 -17 squared

Step-by-step explanation:

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A line with a slope of -2 is written in the form y=mx+b.

yanalaym [24]

Answer:

b = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Here m = - 2 , then

y = - 2x + b ← is the partial equation

To find b substitute (5, - 7 ) into the partial equation

- 7 = - 10 + b ⇒ b = - 7 + 10 = 3

5 0

3 years ago

Find the multiplicative inverse of 9/19

melisa1 [442]

The product of a number and its multiplicative inverse is 1.

$\frac{9}{19} x=1
\\
\\9x=19
\\
\\x= \frac{19}{9}$

7 0

3 years ago

Of all the eighth graders at the Paxton School, 15 played basketball, 9 played volleyball, 10 played soccer, 1 played basket

Elena-2011 [213]

Answer:

32

Step-by-step explanation:

4 0

3 years ago

Researchers report that on average freshman who live on campus gain 15 pounds during their first year in college. You survey 10

neonofarm [45]

Answer: 1.460

Step-by-step explanation:

Given : Researchers report that on average freshman who live on campus gain 15 pounds during their first year in college.

Let $\mu$ represents the population mean .

Then, the set of hypothesis will be:-

$H_0: \mu=15$

$H_a:\mu\neq15$

We assume that this is normal distribution.

Sample size : n = 10, which is a small sample (n<30) ,s o we use t-test.

Sample mean : $\overliene{x}=16.2\ lbs$

Standard deviation : $\sigma=2.6$

The test statistic for population mean for small sample is given by :-

$t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t=\dfrac{16.2-15}{\dfrac{2.6}{\sqrt{10}}}=1.45951276623\approx1.460$

Hence , the value of test statistic = 1.460

4 0

3 years ago

Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago