Answer:
![{ \huge \star} \boxed{\sqrt{6} \times 10 \sqrt{12}} {\huge \star} \\ = \sqrt{6} \times 10 \times \sqrt{6 \times 2} \\ = 6 \times 10 \times \sqrt{2} \\ = \boxed{ 60 \sqrt{2} }](https://tex.z-dn.net/?f=%7B%20%5Chuge%20%5Cstar%7D%20%20%5Cboxed%7B%5Csqrt%7B6%7D%20%20%5Ctimes%2010%20%5Csqrt%7B12%7D%7D%20%7B%5Chuge%20%5Cstar%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B6%7D%20%20%5Ctimes%2010%20%5Ctimes%20%20%5Csqrt%7B6%20%5Ctimes%202%7D%20%20%5C%5C%20%20%3D%206%20%5Ctimes%2010%20%5Ctimes%20%20%5Csqrt%7B2%7D%20%5C%5C%20%3D%20%20%5Cboxed%7B%2060%20%5Csqrt%7B2%7D%20%20%7D)
<h3><u>60√2</u> is the right answer</h3>
Answer:
4.57 x ![10^{4}](https://tex.z-dn.net/?f=10%5E%7B4%7D)
Step-by-step explanation: use ma th way next time and use it to see the steps
7.25 is the constant rate.
I am assuming Michael's interpretation is correct, that you want to find how much gas is used in 4 days knowing how much is used in 5 days. Set up a simple proportion and solve it:
3/4 tank → 5 days
x tank → 4 days
x = 4 * (3/4) / 5 = 3/5 of a tank
In 4 days you use 3/5 of a tank.
Answer:
60.5
Step-by-step explanation:
Ehhh 52.07+8.43=60.5?