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2 years ago

1

2 answers:

7 0

The skull, because it’s an actual skull an actual part of a body, the mold is just a mold of the bone not the actual bone. A leaf print is wrong too. A Dino footprint isn’t part of a dinosoar it’s just an imprint, so the right answer is C skull

Musya8 [376]2 years ago

3 0

Answer:

A perfect mold of a dinosaur bone

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How can one separate and collect the solvent from a salt solution

satela [25.4K]

Simple distillation is a method for separating the solvent from a solution

EXAMPLE: water can be separated from salt solution, because water has a much lower boiling point than salt. When the solution is heated, the water evaporates.

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3 years ago

Object A has a temperature of 287 Kelvin, object B has a temperature of 374 Kelvin. In what direction will thermal energy flow?

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Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.

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2 years ago

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For the following molecules, what is the order of Bronsted acidity, from highest to lowest

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Answer:

Rank these compounds in order of increasing basicity. (Least basic to most basic)

a. C, B, A

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c. C, A, B

d. A, B, C

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Explanation:

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2 years ago

14. In groups, students create dioramas to depict different ecosystems and their physical characteristics. One of the dioramas i

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The answer would be E, it shows students how the different environments appear, since you can visually see it.

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3 years ago

Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

3 years ago