What is the molar mass of AU with a mass of 35.12 g

Why do we need to know these organic molecules? Are they important to living things?

laila [671]

Answer:

<h2>Organic molecules are important to living things because life is based on the properties of carbon. Carbon is an important element because it can </h2><h2>form four covalent bonds. ... The carbon skeletons contain the functional groups that are involved in biochemical reactions.</h2>

Explanation:

<h2>PLEASE MARK ME BRAINLIEST AND FOLLOW ME LOTS OF LOVE FROM MY HEART AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

7 0

3 years ago

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Some animals that live in extremely cold environments protect themselves from freezing by increasing the molality of certain che

lara [203]

Molality is defined as the number of moles of solute dissolved per 1000g(1kg) of solvent.
It is represented by m

$\\ \sf \longmapsto m=\dfrac{Moles\:of\:solute}{Wt\:of\:solvent(in\:g)}\times 1000$

8 0

3 years ago

In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 18.0°C. You identified that the ideal pressure (

Natasha2012 [34]

Answer:

4,38%

small molecular volumes

Decrease

Explanation:

The percent difference between the ideal and real gas is:

(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ 4,38%

This difference is considered significant, and is best explained because argon atoms have relatively small molecular volumes. That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.

Therefore, an increasing in volume will produce an ideal gas behavior. Thus:

If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to decrease

I hope it helps!

5 0

4 years ago

How many theoretical plates produce a chromatography peak eluting at 12.83 min with a width at half-height of 8.7 s

GrogVix [38]

Answer-Figure P38.63a
is a three-dimensional sketch of a birefringent crystal. The dotted lines illustrate how a thin, parallefaced slab of material could be cut from the larger specimen with the crystal’s optic axis parallel to the faces of the plate.”

Sorry if it’s it correct

4 0

2 years ago

How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?

zaharov [31]

Answer:

$m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2$

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

$2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2$

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

$m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2$

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

$4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2$

Best regards!

7 0

3 years ago