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lesya [120]
3 years ago
14

On approximately what day in 28-days cycle is the egg released from the ovary

Chemistry
1 answer:
arsen [322]3 years ago
4 0
This is about 6-12 days after ovulation
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When doing a recrystallization what observations would prompt you to perform a hot filtration?
KATRIN_1 [288]
Answer is: <span>because dissolved compounds can crystallizing from solution during filtration and forming crystals on the filter paper or funnel.
</span>Recrystallization<span> is a technique used to purify chemicals by dissolving both impurities and a compound in an appropriate solvent, either compound or impurities can be removed from the solution, leaving the other behind.</span>
3 0
3 years ago
Read 2 more answers
What is the current in 160V current if the resistance is 20
Karo-lina-s [1.5K]

Answer:

Current, I = 8 A

Explanation:

We have,

Voltage, V = 160 V

Resistance, R = 20 ohms

It is required to find the current. The relation between current, voltage and resistance is called Ohm's law. It is given as :

V=IR

I = current

I=\dfrac{V}{R}\\\\I=\dfrac{160}{20}\\\\I=8\ A

So, the value of current is 8 A.

7 0
2 years ago
12.23 g of ammonia (NH3) are dissolved in enough water to make 560.0 mL of solution. How many moles of NH3 are added to the wate
Karolina [17]

Answer:

0.719 moles of NH₃

Explanation:

Molar mass of ammonia 17 g/mol

Mass of amonia = 12.23 g

Mass / Molar mass = Moles

12.23 g / 17 g/mol = 0.719 moles

4 0
3 years ago
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Cerrena [4.2K]
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6 0
2 years ago
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?Al + ?H2SO4 → ?Al2(SO4)3 +3H2
AfilCa [17]

The answer is: 27 grams of aluminium.

Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

n(H₂) = 1.5 mol; amount of hydrogen.

Form chemical reaction: n(Al) : n(H₂) = 2 : 3.

n(Al) = 2 · 1.5 mol ÷ 3.

n(Al) = 1.0 mol; amount of aluminium.

m(Al) = n(Al) · M(Al).

m(Al) = 1 mol · 27 g/mol.

m(Al) = 27 g; mass of aluminium.

5 0
2 years ago
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